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Aleks04 [339]
3 years ago
5

14:2= 20: wat is the equivalent ratio​

Mathematics
2 answers:
lina2011 [118]3 years ago
6 0
By cross multiplying, the answer should be 2.9
sukhopar [10]3 years ago
6 0

Answer:

\large\boxed{14:2=20:\dfrac{20}{7}}

Step-by-step explanation:

14:2=20:x\\\\\dfrac{14\!\!\!\!\!\diagup^7}{2\!\!\!\!\diagup_1}=\dfrac{20}{x}\\\\\dfrac{7}{1}=\dfrac{20}{x}\qquad\text{cross multiply}\\\\7x=(20)(1)\\\\7x=20\qquad\text{divide both sides by 7}\\\\x=\dfrac{20}{7}

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3/10 that's equivalent
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3 years ago
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What is the midpoint of a segment with These endpoints (-6,-9) and (16,5)
lora16 [44]

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7 0
3 years ago
Help find length of ac n explain please thanks
Debora [2.8K]

Answer:

AC = 12.5 cm

Step-by-step explanation:

use cosine law c^2 = a^2 + b^2 − 2ab cos(C)

c^2 = 6^2 + 10^2 - 2(6)(10)(cosin100)

c^2 = 156.84

c= √156.84

c= 12.5 cm

The cosine rule is used when we are given either three sides or two sides and the included angle.

6 0
3 years ago
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Ls Figure A'B'C'D' a translation of Figure ABCD? (Click in the picture to see the rest
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6 0
3 years ago
) Set up a double integral for calculating the flux of F=3xi+yj+zk through the part of the surface z=−5x−2y+2 above the triangle
Fynjy0 [20]

The surface (call it S) is a triangle with vertices at the points

x=0,y=0\implies z=2\implies(0,0,2)

x=0,y=2\implies z=-2\implies(0,2,-2)

x=2,y=0\implies z=-8\implies(2,0,-8)

Parameterize S by

\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)

with 0\le u\le1 and 0\le v\le1. Take the normal vector to S to be

\vec s_v\times\vec s_u=(20v,8v,4v)

Then the flux of \vec F across S is

\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^1\int_0^1(6-6v,2v-2uv,-8+6v+4uv)\cdot(20v,8v,4v)\,\mathrm du\,\mathrm dv

=\displaystyle8\int_0^1\int_0^1(11v-10v^2)\,\mathrm du\,\mathrm dv=\boxed{\frac{52}3}

8 0
4 years ago
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