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FromTheMoon [43]
3 years ago
14

Someone help me. ty ​

Mathematics
2 answers:
-Dominant- [34]3 years ago
7 0

Answer:

B

Step-by-step explanation:

Gnom [1K]3 years ago
6 0
The correct answer is B
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Prove that H c G is a normal subgroup if and only if every left coset is a right coset, i.e., aH = Ha for all a e G
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\Rightarrow

Suppose first that H\subset G is a normal subgroup. Then by definition we must have for all a\in H, xax^{-1} \in H for every x\in G. Let a\in G and choose (ab)\in aH (b\in H). By hypothesis we have aba^{-1} =abbb^{-1}a^{-1}=(ab)b(ab)^{-1} \in H, i.e. aba^{-1}=c for some c\in H, thus ab=ca \in Ha. So we have aH\subset Ha. You can prove Ha\subset aH in the same way.

\Leftarrow

Suppose aH=Ha for all a\in G. Let h\in H, we have to prove  aha^{-1} \in H for every a\in G. So, let a\in G. We have that ha^{-1} =a^{-1}h' for some h'\in H (by the hypothesis). hence we have aha^{-1}=h' \in H. Because a was chosen arbitrarily  we have the desired .

 

5 0
3 years ago
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anastassius [24]
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