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3 years ago

Someone help me. ty

Mathematics

2 answers:

-Dominant- [34]3 years ago

7 0

Answer:

Step-by-step explanation:

Gnom [1K]3 years ago

6 0

The correct answer is B

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True or false when a figure has an enlargement, the figure gets smaller

Stels [109]

Answer:

False.

Step-by-step explanation:

False.

To enlarge means to become bigger.

8 0

3 years ago

Read 2 more answers

Find the derivative of <img src="https://tex.z-dn.net/?f=tan%5E%7B-1%7D%20x" id="TexFormula1" title="tan^{-1} x" alt="tan^{-1} x

sladkih [1.3K]

$\huge{\color{magenta}{\fbox{\textsf{\textbf{Answer}}}}}$

$\frak {\huge{ \frac{1}{1 + {x}^{2} } }}$

Step-by-step explanation:

$\sf let \: f(x) = { \tan }^{ - 1} x \\ \\ \sf f(x + h) = { \tan}^{ - 1} (x + h)$

$\sf f'(x) = \frac{f(x+h) - f(x) }{h}$

$\sf \implies \lim_{ h \to 0 } \frac{ { \tan }^{ - 1}(x + h) - { \tan}^{ - 1}x }{h} \\ \\ \\ \sf \implies \lim_ {h \to 0} \frac{ { \tan}^{ - 1} \frac{x + h - x}{1 + (x + h)x} }{h}$

By using

$\sf { \tan}^{ - 1} x - { \tan}^{ - 1} y = \\ \sf { \tan}^{ - 1} \frac{x - y}{1 + xy} formula$

$\sf \implies \large \lim_{h \to0 } \frac{ { \tan}^{ - 1} \frac{h}{1 + hx + {x}^{2} } }{h} \\ \\ \\ \sf \implies \large{\lim_{h \to0} } \frac{ { \tan}^{ - 1} \frac{h}{1 + hx + {x}^{2} } }{ \frac{h}{1 + hx + {x}^{2} } \times (1 + hx + {x}^{2} )} \\ \\ \\ \sf \implies \large \lim_{h \to0} \frac{ { \tan}^{ - 1} \frac{h}{1 + hx + {x}^{2} } }{ \frac{h}{1 + hx + {x}^{2} } } + \lim_{h \to0} \frac{1}{1 + hx + {x}^{2} }$

Now putting the value of h = 0

$\sf \large \implies 0 + \frac{1}{1 + 0 + {x}^{2} } \\ \\ \\ \purple{ \boxed { \implies \frac{1}{1 + {x}^{2} } }}$

6 0

2 years ago

The scale of a drawing is 2 cm : 1 mm. Is the scale drawing larger or smaller than the actual object? Explain.

PSYCHO15rus [73]

The scale drawing is smaller than the actual object because a scale is an estimation on where an object is. We can't draw 1 mile that would be impossible to draw a whole drawing based on one location.

7 0

3 years ago

Read 2 more answers

Point P is located at (−2, 7), and point R is located at (1, 0). Find the y value for the point Q that is located two over three

irinina [24]

Answer:

7/3

Step-by-step explanation:

The distances have the ratio ...

(Q -P) = (2/3)(R -P)

Q = P +(2/3)R -(2/3)P = (2R +P)/3

Qy = (2Ry +Py)/3 = (2·0 +7)/3 = 7/3

8 0

3 years ago

5 less than the square of a number

yanalaym [24]

x^2 - 5 this will be the equation formed.

<h3>What is exponents?</h3>

An exponent is the number of times a number is multiplied by itself. For example, 2 to the third (written as 23) means: 2 x 2 x 2 = 8. 23 is not the same as 2 x 3 = 6. Remember that a number raised to the power of one is itself.

<h3>Calculation </h3>

let the number be x

x^2 - 5 this will be the equation formed

learn more about exponents here :

brainly.com/question/5497425

#SPJ1

6 0

1 year ago

Someone help me. ty ​

Someone help me. ty