Answer:
Add
−
1
and
2
.
2
,
2
s
+
1
Step-by-step explanation:
The correct choice is C .
1) The triangles are similar, so correponding sides have the same ratio.
.. 3x/20 = (4x +2)/28
.. 3x/5 = (4x +2)/7 . . . . . . . multiply by 4
.. 7*3x = 5(4x +2) . . . . . . . multiply by 35 = 5*7
.. 21x = 20x +10 . . . . . . . . eliminate parentheses
.. x = 10 . . . . . . . . . . . . . . . subtract 20x
2) The triangles are similar, so corresponding measures have the same ratio.
.. x/42 = 10/15
.. x = 42*(10/15) = 28
3) The third angle of triangle ABC is 180° -20° -80° = 80°. Then two of the angles of ABC match those of JKL. The 3rd answer selection is appropriate.
Answer:
A. Area of ABCD = 240 
B. 60 cm
C. 36 cm
D. 50 cm
Step-by-step explanation:
Given: AB = 24cm BC = 10cm and AE = 13cm.
A. Since a rectangle is a 2 dimensional figure, it has no volume but area.
So that,
the area of the rectangle ABCD = length x width
= 24 x 10
= 240 
B. To calculate the circumference of the BCD triangle, apply the Pythagoras theorem to determine BD.
=
+ 
=
+ 
= 676
BD = 
= 26
BD = 26 cm
so that,
the circumference of BCD = 10 + 24 + 26
= 60 cm
C. To calculate the circumference of the BEC triangle,
AC = 26 cm, AE = 13 cm
CE = 26 - 13
= 13 cm
CE = 13 cm
The circumference of the BEC triangle = 13 + 13 + 10
= 36 cm
D. The circumference of the DEC triangle = 13 + 13 + 24
= 50 cm