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Sati [7]
2 years ago
15

Someone help me with the question please

Mathematics
2 answers:
Ratling [72]2 years ago
8 0

Answer:

1. 1/6

2. 10/36

3. 1/12

Step-by-step explanation:

iris [78.8K]2 years ago
8 0

Answer:

What question do you need help with?

Step-by-step explanation:

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Pls help!
Misha Larkins [42]

Answer:

11/32

Step-by-step explanation:

I took the test Please make brainlyest if can

4 0
2 years ago
Solve math thank you.
Masja [62]

Answer:

Put a picture of the whole thing

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Each letter of the English alphabet is written on a scrap of paper and put in a hat p(j)= 1/26 what type of probability is illus
Marysya12 [62]
In the situation '<span>Each letter of the English alphabet is written on a scrap of paper and put in a hat p(j)= 1/26', the type of probability illustrated is classical or mathematical probability. This is because 1 represents the number of expected outcomes of the event while 26 represents the total number of outcomes.</span>
8 0
3 years ago
Read 2 more answers
You roll a 6-sided die.
Lerok [7]

Answer:

\huge\boxed{\text{P(not factor of 35) = } \frac{2}{3}}

Step-by-step explanation:

We can use basic probability to find the probability that this roll is not a factor of 35.

First off, we know that with a six sided die there are 6 possible things we can roll.

1, 2, 3, 4, 5, or 6

Now, what are the factors of 35? The factors of 35 will be any whole number that can be multiplied by another whole number to get 35.

  • We know 1 \cdot 35 = 35, so two factors are 1 and 35.
  • We know 5 \cdot 7 = 35, so two factors are 5 and 7.

Therefore, the factors of 35 are 1, 5, 7, 35.

Both 5 and 7 are inside the range of 1-6. So the probability of rolling a side that's a factor of 35 will be  \frac{2}{6} = \frac{1}{3} since there are two factors and 6 possible options.

This means, logically, there is a  \frac{4}{6} = \frac{2}{3}  chance of not rolling a factor of 35.

Hope this helped!

5 0
3 years ago
How do I set this up to solve as a linear equation?
NISA [10]
I don't see any numbers to set up in an equation or letters
4 0
3 years ago
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