A, 30. The triangle inside the circle is a perfect triangle (I mean it has three 60-degree angle ) so the angle POQ is 60degree, and since PQ is tangent to the circle at Q, the angle OQP is 90 degree, plus angle x, angle POQ and angle OQP formed a triangle, these three angle plus together should be 180 degree. You as a result would get 30
y = 2x^2 - 12x + 46
Compare your equation with the standard form of the equation:
y = ax^2 + bx + c
For your equation, a = 2, b = -12, c = 46.
The vertex has x-coordinate -b/(2a).
The x-coordinate of the vertex is: -(-12)/(2 * 2) = 12/4 = 3
Now we plug in x = 3 into the function to find the y-coordinate of the vertex.
y = 2(3^2) - 12(3) + 46
y = 2(9) - 36 + 46
y = 18 - 36 + 46
y = 28
The vertex is (3, 28)
The answer is -2/5; hope this helps
Answer:
Step-by-step explanation:
I did this too ✌️✌️
