Solve the system of equations and enter the solution as an ordered pair. 2x

The average human gestation period is 270 days with a standard deviation of 9 days. The period is normally distributed. What is

Anna35 [415]

Answer:

Probability that a randomly selected woman's gestation period will be between 261 and 279 days is 0.68.

Step-by-step explanation:

We are given that the average human gestation period is 270 days with a standard deviation of 9 days. The period is normally distributed.

Firstly, Let X = women's gestation period

The z score probability distribution for is given by;

Z = $\frac{ X - \mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = average gestation period = 270 days

$\sigma$ = standard deviation = 9 days

Probability that a randomly selected woman's gestation period will be between 261 and 279 days is given by = P(261 < X < 279) = P(X < 279) - P(X $\leq$ 261)

P(X < 279) = P( $\frac{ X - \mu}{\sigma}$ < $\frac{279-270}{9}$ ) = P(Z < 1) = 0.84134

P(X $\leq$ 261) = P( $\frac{ X - \mu}{\sigma}$ $\leq$ $\frac{261-270}{9}$ ) = P(Z $\leq$ -1) = 1 - P(Z < 1)

= 1 - 0.84134 = 0.15866

Therefore, P(261 < X < 279) = 0.84134 - 0.15866 = 0.68

Hence, probability that a randomly selected woman's gestation period will be between 261 and 279 days is 0.68.

3 0

3 years ago

I need some help... Algebra Hw

Svet_ta [14]

Answer:can't see no 1

Step-by-step explanation:

2=A

3=c

4 0

2 years ago

Choose the inequality that represents the following graph.

11Alexandr11 [23.1K]

Answer:

b is the answer I believe so because it have to be greater than 0

Step-by-step explanation:

I hope it's right and if not my bad

4 0

2 years ago

A trimming operation at a local manufacturer produces rods whose length conforms to unifrom distribution with a minimum of 18cm

MariettaO [177]

Answer:

The probability that randomly selected road will be at least 25.8 cm long will be 48%.

Step-by-step explanation:

Given: uniform distribution with min and max values of 18 and 33 respectively.

To find : probability density for upper cumulative frequency i.e 25.8 at least means x $\geq$ 25.8 upto 33 cm i.e the maximum limit of function.

Solution:

we have by definition , of uniform distribution

we get , probability density function defines as :

F(x,a,b)= $\frac{1}{b-a}$ $a\leq x\leq b$

=1/(33-18)=1/15=0.0667.

this is probability density function.

here the x=25.8 , a=18 and b=33

for lower cumulative frequency it defines as ;

P(x,a,b)= $\frac{x-a}{b-a}$ =25.8-18/33-18=0.52

for upper cumulative frequency it defines as ;

Q(x,a,b)=b-x/b-a=33-25.8/33-18=0.48

here at least 25.8 cm probability means it should be greater than a value(18cm) hence it is provided by the upper cumulative frequency

i.e. Q(x,a,b)=0.48

The probability that randomly selected road will be at least 25.8 cm long will be 48%.

7 0

2 years ago

Use the relationship between the angles in the figure to answer the question.

Brut [27]

Answer:

x + 49 + 28 = 180

Step-by-step explanation:

The angles on a straight line with x° are 28° and 49° respectively, side by side with x°. This is because, vertical angles are equal. Therefore, the angle vertically opposite 28° and 49° are equal to 28° and 49° respectively.

Therefore, since angles on a straight line is 180°, thus:

x + 49 + 28 = 180

6 0

2 years ago

Read 2 more answers

Solve the system of equations and enter the solution as an ordered pair. 2x - 5y = -6 8x + 3y = 68