Question

Emergency !! y=2x^(2)-12x+46 please put steps

Answer 1

y = 2x^2 - 12x + 46

Compare your equation with the standard form of the equation:

y = ax^2 + bx + c

For your equation, a = 2, b = -12, c = 46.

The vertex has x-coordinate -b/(2a).

The x-coordinate of the vertex is: -(-12)/(2 * 2) = 12/4 = 3

Now we plug in x = 3 into the function to find the y-coordinate of the vertex.

y = 2(3^2) - 12(3) + 46

y = 2(9) - 36 + 46

y = 18 - 36 + 46

y = 28

The vertex is (3, 28)