All categories

3 years ago

Emergency !! y=2x^(2)-12x+46 please put steps

Mathematics

1 answer:

Kamila [148]3 years ago

7 0

y = 2x^2 - 12x + 46

Compare your equation with the standard form of the equation:

y = ax^2 + bx + c

For your equation, a = 2, b = -12, c = 46.

The vertex has x-coordinate -b/(2a).

The x-coordinate of the vertex is: -(-12)/(2 * 2) = 12/4 = 3

Now we plug in x = 3 into the function to find the y-coordinate of the vertex.

y = 2(3^2) - 12(3) + 46

y = 2(9) - 36 + 46

y = 18 - 36 + 46

y = 28

The vertex is (3, 28)

You might be interested in

3 lbs, 7 ounces = ____ ounces

Dafna1 [17]

Answer:

one pound is equal to 16 oz

(3x16= 48)

(48+7=55)

55 ounces

5 0

2 years ago

Read 2 more answers

Work out m and c for the line: y = x + 4

OLEGan [10]

Answer:

Step-by-step explanation:

6 0

3 years ago

PLEASE ANSWER THIS I WILL GIVE YOU 7 POINTS

MissTica

Answer:

tell me the question

Step-by-step explanation:

l am ready for you

6 0

2 years ago

Marissa is painting her rectangular patio, with the exception of a bench that does not need to be painted:

mars1129 [50]

Answer:

A = (x + 15)(x + 10) − 5

Step-by-step explanation:

(x+15)(x+10)-5=A would be a solution

To make this easier, let's assign x a value. Let's say 3.

(3+15)(3+10)-5=A

(18)(13)-5=A

234-5=A

A=229

Now with this, we put x in the answer choice and the answer that gives an area of 229 is correct.

A. A=(3+20)(3+10)+12=(23)(13)+12=299+12=311 Answer A is wrong.

B. A=(3+20)(3+10)-12=(23)(13)-12=299-12=287 Answer B is wrong.

C. A=(3+26)(3+15)=(29)(18)=522 Answer C is wrong.

D. A=(3+14)(3+8)=(17)(11)=187 Answer D is wrong.

It's either I'm wrong or the answer choices are wrong.

New answer choices!

A. A=(3+20)(3+11)

=(23)(14)=322 Answer A is wrong.

B. A=(3+15)(3+10)+5

=(18)(13)+5=234+5=239 Answer B is wrong.

C. A=(3+15)(3+10)−5

=(18)(13)-5=234-5=229 Answer C is correct.

D. A=(3+9)(3+10)=(12)(13)=156 Answer D is wrong.

5 0

3 years ago

Let v⃗ 1=⎡⎣⎢033⎤⎦⎥,v⃗ 2=⎡⎣⎢1−10⎤⎦⎥,v⃗ 3=⎡⎣⎢30−3⎤⎦⎥ be eigenvectors of the matrix A which correspond to the eigenvalues λ1=−1, λ2

kaheart [24]

Answer:

- x as a linear combination :

x = -1 v1+ 0 v2+ 1 v3.

- Transpose Ax = (12, -6, -6)

Step-by-step explanation:

Given v1 = (0 3 3),v2 = (1 −1 0), v3 = (3 0 −3) be eigenvectors of the matrix A which correspond to the eigenvalues λ1 = −1, λ2 = 0, and λ3 = 1, respectively, and let x = (−2 −4 0). Express x as a linear combination of v1, v2, and v3, and find Ax .

To write x as a linear combination of v1, v2, and v3

x = -1 v1+ 0 v2+ 1 v3.

To find Ax

Write A = (0 ......3 ......3 )

...................(1 ......-1 ......0)

...................(3 ......0......-3)

Since transpose x = (-2, 4, 0)

Ax =......... (0 ......3......3 )(-2)

...................(1 ......-1 ......0)(4)

...................(3 ......0......-3)(0)

= (0×-2 + 3×4 + 3×0)

...(1×-2 + -1×4 + 0×0)

.. (3×-2 + 0×4 + -3×0)

As = (12)

....(-6)

Transpose Ax = (12, -6, -6)

7 0

3 years ago