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Leto [7]
3 years ago
9

Define the term proportional

Mathematics
1 answer:
Zepler [3.9K]3 years ago
4 0
Corresponding in size or amount to something else
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Please give the numbers?
4 0
4 years ago
Find the slope from the table:
Aleonysh [2.5K]

Answer:

B! \frac{-5}{3}

Step-by-step explanation:

Because 10 minus 5 (from the y column) is -5. And -5 - (-2) is +3. So you get -5 over 3 (\frac{-5}{3}). which is B!

Can you give me brainliest please?? :)

5 0
2 years ago
can someone explain scientific notation to me? i dont know if this would be a right question but i need it to be explained
Nikitich [7]

Answer:

In step by step explanation

Step-by-step explanation:

Move your decimal until you have one non-zero number left of your deciaml point the number of times you moved you decimal to the left will be the exponent you put attached to a ten.

8 0
3 years ago
You roll two fair dice, one green and one red. (a) Are the outcomes on the dice independent? Yes No (b) Find P(1 on green die an
ASHA 777 [7]

Answer:

a

  Yes

b

 P(1 \& 5) = \frac{1}{36}

c

 P(5 \& 1) = \frac{1}{36}

d

 P(5 \& 1 | 1\& 5  ) = \frac{1}{18}

Step-by-step explanation:

From the question we are told that

     Two fair dice, one green and one red were rolled

Generally the  outcomes on the dice independent because the outcome on the first dice is not affected by the second die

Generally the  probability of getting a 1  on a dice rolled is  P(1) =  \frac{1}{6}

the  probability of getting a 5 on a dice rolled is  P(5) =  \frac{1}{6}

Generally the probability of P(1 on green die and 5 on red die) is mathematically represented as

         P(1 \& 5) = \frac{1}{6}  *\frac{1}{6}

         P(1 \& 5) = \frac{1}{36}

Generally the probability of P(5 on green die and 1 on red die) is mathematically represented as

          P(5 \& 1) = \frac{1}{6}  *\frac{1}{6}

         P(5 \& 1) = \frac{1}{36}

Generally the probability of P((1 on green die and 5 on red die) or (5 on green die and 1 on red die)) is mathematically represented as

          P(5 \& 1 | 1\& 5  ) = \frac{1}{36} + \frac{1}{36}

         P(5 \& 1 | 1\& 5  ) = \frac{1}{18}

8 0
3 years ago
How do you find the total sum of squared values?
tester [92]

Answer:

Step-by-step explanation:

\sum^{12}_{r=1} r^2 = \frac{12(12+1)(2*12+1)}{6}= A

\sum_{r=3}^{12}= \sum_{r=1}^{12} - (r_1+r_2)

r_1= 1^2

r_2= 2^2

you do your math!!

7 0
3 years ago
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