Step-by-step explanation:
solution:-  from LHS 1-cos²x/sinx 
∵ 1-cos²x = sin²x 
∴ sin²x /sinx = sinx 
from RHS tanx × cosx
∵tanx = sinx×cosx 
∴ sinx/ cosx × cosx = sinx 
Since, LHS = RHS proved ___
 
        
             
        
        
        
Answer:

Step-by-step explanation:
Given


Required
Write the equation of the function 
Express the function as:

In: 

 --- (1)
In 

 --- (2)
Divide (2) by (1)






Substitute 5/6 for b in (1)






The function: 

 
        
             
        
        
        
Please, for clarity, use " ^ " to denote exponentiation:
Correct format: x^4*y*(4) = y*x^2*(13) 
This is an educated guess regarding what you meant to share. Please err on the side of using more parentheses ( ) to show which math operations are to be done first.
Your (x+y)2, better written as (x+y)^2, equals x^2 + 2xy + y^2, when expanded.
The question here is whether you can find this x^2 + 2xy + y^2 in your 
"X4y(4) = yx2(13)"
Please lend a hand here. If at all possible obtain an image of the original version of this problem and share it. That's the only way to ensure that your helpers won't have to guess what the problem actually looks like.
 
        
             
        
        
        
Answer:
275
Step-by-step explanation:
6+23=29 and 32-25=7
29 x 7 = 203
203 + 72 = 275
The final answer is 275. 
Hope this helps!