probability of one go on vacation and one does not go on vacation is 0.2356 and probability none of them go on vacation is 0.1444
According to a survey, 62% of americans go on vacation each .
two americans are chosen from a group of 100 americans.
what is the probability that one or both of the people chosen does not go on vacation each ?
62% americans go on vacation t
hen 38% americans does not go on vacation
Total group of americans is 100
out of 100 americans 62 go on vacation and 38 does not go on vacation
probability of one go on vacation and one does not go on vacation
= 0.62*0.38
=0.2356
probability none of them go on vacation
= 0.38*0.38
=0.1444
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Answer:
The graph in the attached figure
Step-by-step explanation:
we have
Solve for x
The solution is the interval ------> (4,∞)
All real numbers greater than 4
In a number line, the solution is the shaded area at right of x=4 (open circle, the number 4 is not included in the solution)
see the attached figure
Answer:
1/20
Step-by-step explanation:
