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solmaris [256]
4 years ago
7

What is the final amount of $105.00 that is put into a savings account with 8% interest rate for 25 years, if the interest is co

mpounded 4 times per year?
Mathematics
2 answers:
Tema [17]4 years ago
7 0
A=105×(1+0.08÷4)^(4×25)
A=760.68
zubka84 [21]4 years ago
6 0

Answer:

Given: The principal amount (P) = $ 105.00, rate of interest(r) = 8% and t= 25 years and number of times interest compounded per year (n) =4.

Use formula to find the final amount i.e,

A =P(1+\frac{r}{100n})^{nt} ......[1] ; where r is the rate of interest , n is the number of times interest compounded per year and P is the Principal.

Now, substitute the given values of P , r, n and t in [1] we get;

A = 105 \times (1+\frac{8}{100 \times 4})^{4\times 25}

or

A =105 \times (1+\frac{8}{400})^{100}

Simplify:

A = $ 760.687842416

therefore, the final amount is $ 760.68 (approx.)



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Step-by-step explanation:

given that both angles are the same, it is an equilateral right triangle.

we can use Pythagorean's theorem

a^2 + b^2 = c^2\\(\sqrt{6})^2+(\sqrt{6})^2= c^2\\  12 = c^2 \\c = \sqrt{12} = \sqrt{4*3} = 2\sqrt{3}

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An adult elephant eats about 300 pounds of food each day. Write an expression to represent the number of pounds of food a herd o
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Can anyone help me with question 7 please?
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c is the answer

Step-by-step explanation:

I hope it may helps you

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A soda bottling plant fills cans labeled to contain 12 ounces of soda. The filling machine varies and does not fill each can wit
AnnZ [28]

Answer:

12.1-1.64\frac{0.35}{\sqrt{50}}=12.019  

12.1+1.64\frac{0.35}{\sqrt{50}}=12.181  

So on this case the 90% confidence interval would be given by (12.019;12.181)

And we can conclude at 90% of confidence that the true mean is between (12.019, 12.181) and since the lower limit is higher than 12 we can conclude that the specification is not satisfied

Step-by-step explanation:

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X=12.1 represent the sample mean  

\mu population mean (variable of interest)  

\sigma=0.35 represent the population standard deviation  

n=50 represent the sample size  

Solution to the problem  

The confidence interval for the mean is given by the following formula:  

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)  

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that z_{\alpha/2}=1.64  

Now we have everything in order to replace into formula (1):  

12.1-1.64\frac{0.35}{\sqrt{50}}=12.019  

12.1+1.64\frac{0.35}{\sqrt{50}}=12.181  

So on this case the 90% confidence interval would be given by (12.019;12.181)

And we can conclude at 90% of confidence that the true mean is between (12.019, 12.181) and since the lower limit is higher than 12 we can conclude that the specification is not satisfied

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Answer:

$10, $10, $10, $15, $15, $20, $100,  the central tendency is  $15,

Step-by-step explanation:

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