Given mean = 0 C and standard deviation = 1.00
To find probability that a random selected thermometer read less than 0.53, we need to find z-value corresponding to 0.53 first.
z= 
So, P(x<0.53) = P(z<0.53) = 0.701944
Similarly P(x>-1.11)=P(z>-1.11) = 1-P(z<-1.11) = 0.8665
For finding probability for in between values, we have to subtract smaller one from larger one.
P(1.00<x<2.25) = P(1.00<z<2.25) = P(z<2.25)- P(z<1.00) = 0.9878 - 0.8413 = 0.1465
P(x>1.71) = P(z>1.71) = 1-P(z<1.71) = 1-0.9564 = 0.0436
P(x<-0.23 or x>0.23) = P(z<-0.23 or z>0.23) =P(z<-0.23)+P(z>0.23) = 0.409+0.409 = 0.918
This can be solve using cosine lawbut first let as solve the included angle in the triangle form
angle = 180 - 42angle = 138
c^2 = a^2 + b^2 - 2ab(cos angle)c^2 = 150^2 + 70^2 - 2(150)(70)cos(138)C^2 = 43006.04c = sqrt(43006.04)c = 207.37 mile
directionsin (x) / 70 = sin (138)/ 207.37sin x = 0.2259x = arcsin(0.2259)x = 13.05 degree north of west
The answer is c. -4b + 4b
So, the area of a circle is a=pi r^2
so do that and get a=pi(4)
and since the circle touches the edge of the rectangle, the rectangle is 4 cm tall, so 4*8 is 32 and pi(4) is about 12.56, so 32-12.56 is 19.44, and I believe that is the answer. (19.4)
I got the answer to be 0.9. To get the mean, you add up all the data and then divide it by the number of numbers in you data, so I did 0.5+0.7+1.0+1.7+0.6+1.0=0.8 and then divided by 7, giving me 0.9.
