Answer:
Exercise 1:
base [b]=8cm
perpendicular [p]=6cm
hypotenuse [h]=?
<u>By</u><u> </u><u>using</u><u> </u><u>Pythagoras</u><u> </u><u>law</u>
h²=p²+b²
h²=6²+8²
h=√100
h=10cm
<u>So</u><u> </u><u>another</u><u> </u><u>side's</u><u> </u><u>length</u><u> </u><u>is</u><u> </u><u>1</u><u>0</u><u>c</u><u>m</u>
<u>Exercise</u><u> </u><u>2</u><u>:</u>
base [b]=6m
perpendicular [p]=bm
hypotenuse [h]=8m
By using Pythagoras law
h²=p²+b²
8²=b²+6²
b²=8²-6²
b=√28=2√7 0r 5.29 or 5.3
So height of kite is√<u>28</u><u>o</u><u>r</u><u> </u><u>2√7 0r 5.29 or 5.3 m</u>
Step-by-step explanation:
[Note: thanks for translating]
Answer: 3.97000947 × 10^4
Answer:
1. 8.85 quarts
2. 44.25%
Step-by-step explanation:
In 15 quarts of a solution with percentage of antifreeze = 35%
Amount of antifreeze = 35% × 15
= 0.35 × 15
= 5.25 quarts
that solution is mixed with 5 quarts of a solution with percentage of antifreeze = 72%
Amount of antifreeze = 72% × 5
= 0.72 × 5
= 3.6 quarts
Total amount of mixture = 15 quarts + 5 quarts = 20 quarts
1. Now we will calculate the total amount of antifreeze in the resulting mixture.
= 5.25 + 3.6 = 8.85 quarts
2. The percentage of the resulting mixture is antifreeze
= 
= 44.25%
1. total amount of antifreeze is 8.85 quarts
2. the percentage of antifreeze is 44.25%
Answer:
A, complementary angles sum up to 90°