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Schach [20]
2 years ago
12

Due to delays a company had to extend a project from 28 days to 76 days. What was the percentage increase in time to complete th

e project. Round your answer to the nearest tenth.
Mathematics
1 answer:
mr Goodwill [35]2 years ago
3 0

Answer: 171.4\%

Step-by-step explanation:

Given

Time is extended from 28 days to 76 days

The percentage increase is given by

\Rightarrow \dfrac{\text{New-original value}}{\text{original value}}\times 100

Putting values

\Rightarrow \dfrac{76-28}{28}\times 100=\dfrac{48}{28}\times 100\\\\\Rightarrow 171.4\%

Thus, the percentage increase in time is 171.4\%

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A triangle has an area of 36 cm². The base and height are scaled by a factor of 5.
ahrayia [7]
Triangle Area = .5 * (base * height)
36 = (base * height) / 2
So let's say base = 9 height 8
If base and height are scaled by a factor if 5 than
base = 45 height 40 and
area = .5 * (45 * 40)
area = 900

Basically, the area increases by a factor of 25.
The base increases by 5 and the height increases by 5 so the area increases by 5*5 = 25

4 0
3 years ago
When 300 college students were surveyed, 220 said they own their car. Find a point estimate for p, the population proportion of
Scilla [17]

\text{Hello there!}\\\\\text{Point estimates would be represented as:}\,\,p=\frac{x}{t}\\\\\text{"x" would represent the value you know}\\\\\text{"t" would represent your total}\\\\\text{To find your point value, you would divide 220 by 300}\\\\220\div300=0.73333333\\\\\text{Round to the nearest thousandths place}\\\\\boxed{0.733}

4 0
3 years ago
A random sample of 121 automobiles traveling on an interstate showed an average speed of 73 mph. from past information, it is kn
tatiyna

121 is big enough to assume normality and not worry about the t distribution. By the 68-95-99.7 rule a 95% confidence interval includes plus or minus two standard deviations. So 95% of the cars will be in the mph range


(73 - 2 \cdot 11, 73 + 2 \cdot 11) = (51,95)


The question is a bit vague, but it seems we're being asked for the 95% confidence interval on the average of 121 cars. The 121 is a hint of course.


The standard deviation of the average is in general the standard deviation of the individual samples divided by the square root of n:


\sigma = \dfrac{ 11}{\sqrt{121}} = 1


So repeating our experiment of taking the average 121 cars over and over, we expect 95% of the averages to be in the mph range


(73 - 2 \cdot 1, 73 + 2 \cdot 1) = (71,75)


That's probably the answer they're looking for.



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vlabodo [156]
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Answer:

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Step-by-step explanation:

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