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kipiarov [429]
3 years ago
13

Please help me!!! !!!

Mathematics
1 answer:
eimsori [14]3 years ago
3 0

1   \div 8
pounds of candy for each
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The area of a parallelogram is A = bh. Solve for h (height) in this formula.
Kryger [21]
A/b=h
therefore the height of a parallelogram is equal to the area divided by the base
6 0
3 years ago
A rectangular field is fully enclosed with 218 meters of fencing. The length of the field is
mestny [16]

The length and width of a rectangular field fully enclosed with 218 metes fencing  are 63 meters and 46 meters respectively.

The perimeter of a rectangle is the sum of the whole four sides. Therefore, the perimeter of a rectangle is defined as follows:

  • perimeter = 2(l + w)

where

l = length

w = width

perimeter = 218 meters

The length of the field is  17 meters longer than the width, w. Therefore, the length is defined as follows:

  • l = 17 + w

The length and the width can be calculated as follows:

218 = 2(l + w)

218 = 2(17 + w + w)

218 = 34 + 4w

218 - 34 = 4w

184 = 4w

divide both sides by 4

w = 184 / 4

w = 46 meters

length = 17 + 46

length = 63 meters

learn more on rectangle here: brainly.com/question/15989799?referrer=searchResul

8 0
3 years ago
(6x-5y+4)dy+(y-2x-1)dx=0​
Len [333]

(6<em>x</em> - 5<em>y</em> + 4) d<em>y</em> + (<em>y</em> - 2<em>x</em> - 1) d<em>x</em> = 0

(6<em>x</em> - 5<em>y</em> + 4) d<em>y</em> = (2<em>x</em> - <em>y</em> + 1) d<em>x</em>

d<em>y</em>/d<em>x</em> = (2<em>x</em> - <em>y</em> + 1) / (6<em>x</em> - 5<em>y</em> + 4)

Let <em>X</em> = <em>x</em> - <em>a</em> and <em>Y</em> = <em>y</em> - <em>b</em>. We want to find constants <em>a</em> and <em>b</em> such that

d<em>Y</em>/d<em>X</em> = (a rational function)

where the numerator and denominator on the right side are free of constant terms. Substituting <em>x</em> and <em>y</em> in the equation, we have

d<em>Y</em>/d<em>X</em> = (2 (<em>X</em> + <em>a</em>) - (<em>Y</em> + <em>b</em>) + 1) / (6 (<em>X</em> + <em>a</em>) - 5 (<em>Y</em> + <em>b</em>) + 4)

d<em>Y</em>/d<em>X</em> = (2<em>X</em> - <em>Y</em> + 2<em>a</em> - <em>b</em> + 1) / (6<em>X</em> - 5<em>Y</em> + 6<em>a</em> - 5<em>b</em> + 4)

Then we solve for <em>a</em> and <em>b</em> in the system,

2<em>a</em> - <em>b</em> + 1 = 0

6<em>a</em> - 5<em>b</em> + 4 = 0

==>   <em>a</em> = -1/4 and <em>b</em> = 1/2

With these constants, the equation reduces to

d<em>Y</em>/d<em>X</em> = (2<em>X</em> - <em>Y</em>) / (6<em>X</em> - 5<em>Y</em>)

Now substitute <em>Y</em> = <em>VX</em> and d<em>Y</em>/d<em>X</em> = <em>X</em> d<em>V</em>/d<em>X</em> + <em>V</em> :

<em>X</em> d<em>V</em>/d<em>X</em> + <em>V</em> = (2<em>X</em> - <em>VX</em>) / (6<em>X</em> - 5<em>VX</em>)

The equation becomes separable after some simplification:

<em>X</em> d<em>V</em>/d<em>X</em> + <em>V</em> = (2 - <em>V</em>) / (6 - 5<em>V</em>)

<em>X</em> d<em>V</em>/d<em>X</em> = (2 - <em>V</em>) / (6 - 5<em>V</em>) - <em>V</em>

<em>X</em> d<em>V</em>/d<em>X</em> = (2 - <em>V</em> - (6 - 5<em>V</em>)) / (6 - 5<em>V</em>)

<em>X</em> d<em>V</em>/d<em>X</em> = (4<em>V</em> - 4) / (6 - 5<em>V</em>)

- (5<em>V</em> - 6) / (4<em>V</em> - 4) d<em>V</em> = 1/<em>X</em> d<em>X</em>

Integrate both sides:

-5/4 <em>V</em> + 1/4 ln|4<em>V</em> - 4| = ln|<em>X</em>| + <em>C</em>

Extract a constant from the logarithm on the left:

-5/4 <em>V</em> + 1/4 (ln(4) + ln|<em>V</em> - 1|) = ln|<em>X</em>| + <em>C</em>

-5/4 <em>V</em> + 1/4 ln|<em>V</em> - 1| = ln|<em>X</em>| + <em>C</em>

-5<em>V</em> + ln|<em>V</em> - 1| = 4 ln|<em>X</em>| + <em>C</em>

Get this back in terms of <em>Y</em> :

-5<em>Y/X</em> + ln|<em>Y/X</em> - 1| = 4 ln|<em>X</em>| + <em>C</em>

Now get the solution in terms of <em>y</em> and <em>x</em> :

-5 (<em>y</em> - 1/2)/(<em>x</em> + 1/4) + ln|(<em>y</em> - 1/2)/(<em>x</em> + 1/4) - 1| = 4 ln|<em>x</em> + 1/4| + <em>C</em>

<em />

With some manipulation of constants and logarithms, and a bit of algebra, we can rewrite this solution as

-5 (4<em>y</em> - 2)/(4<em>x</em> + 1) + ln|(4<em>y</em> - 4<em>x</em> - 3)/(4<em>x</em> + 1)| = 4 ln|<em>x</em> + 1/4| + 4 ln(4) + <em>C</em>

-5 (4<em>y</em> - 2)/(4<em>x</em> + 1) + ln|(4<em>y</em> - 4<em>x</em> - 3)/(4<em>x</em> + 1)| = 4 ln|4<em>x</em> + 1| + <em>C</em>

-5 (4<em>y</em> - 2)/(4<em>x</em> + 1) + ln|4<em>y</em> - 4<em>x</em> - 3| - ln|4<em>x</em> + 1| = 4 ln|4<em>x</em> + 1| + <em>C</em>

-5 (4<em>y</em> - 2)/(4<em>x</em> + 1) + ln|4<em>y</em> - 4<em>x</em> - 3| = 5 ln|4<em>x</em> + 1| + <em>C</em>

8 0
3 years ago
Subtraction using ten facts
Nonamiya [84]
? what u r saying but think u r saying subtraction facts of 10. Right. 
10-0=10
10-1=9
10-2=8
10-3=7
10-4=6
10-5=5
10-6=4
10-7=3
10-8=2
10-9=1
That is all the basic subtraction 10 facts i know hope it helps.
<3

3 0
3 years ago
A Pharmacist whishes to mix a solution that is 6% Minoxidil. She has on hand 100 ml of 4% solution and wishes to add some 8% sol
dangina [55]

Answer:

100

Step-by-step explanation:

Let x be the amount to be added of the second solution. For every 100ml of it 8 units of minoxidil are added. The total amount of solution will be (100 + x), so the final concentration is given by:

4 / (100 + x) + 0.08x / (100 + x) = 0.06  [Multiplying by (100 + x)]

4 + 0.08x = 6 + 0.06x                            [Transposing terms]

0.08x - 0.06x = 6 - 4                              [ operating]

0.02x = 2                                                 [Dividing by 0.02]

x=100

4 0
3 years ago
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