Answer:
The answer to your question is letter C
Explanation:
Data
Volume = 2 L
Molarity = 0.100 M
Molecular weight Na₂CO₃ = (2 x 23) + (1 x 12) + (3 x 16)
= 46 + 12 + 48
= 106 g
Process
1.- Calculate the grams of Na₂CO₃ needed
106 g ---------------- 1 mol
x ---------------- 0.1 moles
x = (0.1 x 106) / 1
x = 10.6 g
2.- Calculate the grams of Na₂CO₃ needed for 2 liters of solution
10.6 g -------------- 1 liter
x -------------- 2 liters
x = (10.6 x 2) / 1
x = 21.2 grams of Na₂CO₃
A for number 1 and C for number 2 im sorry i dont know the rest. :3
Freeze-Thaw Weathering
This action can widen the cracks in the rock, and when the temperature rises above freezing, the ice thaws, allowing the water to seep further into the cracks. As this process of freezing and thawing happens repeatedly, the rock begins to weaken and eventually breaks apart into angular fragments.
Answer:
The answer is the second picture.
Explanation:
