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Savatey [412]
3 years ago
14

What is usually released as a product in a combustion reaction?

Chemistry
1 answer:
mojhsa [17]3 years ago
4 0
A for number 1 and C for number 2 im sorry i dont know the rest. :3
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Which of these agreements has goals of peace and shared scientific research?
Jet001 [13]

Option C, Antarctic Treaty System, is the right answer.

The Antarctic Treaty System, control global connections with regard to Antarctica; the only continent of the earth without the native population of human beings. In other words, the ATS is the entire system of adjustments developed for the intention of managing associations among states in the Antarctic. The main goal of the ATS is to guarantee "in the affair of all humankind that Antarctica shall proceed always to be practised completely for peaceful objectives and shall not become the view or gadget of universal disharmony.

8 0
3 years ago
Read 2 more answers
Two isotopes of lithium are found in nature Li6 has a mass of 6. 02u and Li7 has a mass of 7.02u . Use the atomic weight of lith
alexandr402 [8]

The isotope that is more abundant, given the data is isotope Li7

<h3>Assumption</h3>
  • Let Li6 be isotope A
  • Let Li7 be isotope B

<h3>How to determine whiche isotope is more abundant</h3>
  • Molar mass of isotope A (Li6) = 6.02 u
  • Molar mass of isotope B (Li7) = 7.02 u
  • Atomic mass of lithium = 6.94 u
  • Abundance of A = A%
  • Abundance of B = (100 - A)%

Atomic mass = [(mass of A × A%) / 100] + [(mass of B × B%) / 100]

6.94 = [(6.02 × A%) / 100] + [(7.02 × (100 - A)) / 100]

6.94 = [6.02A% / 100] + [702 - 7.02A% / 100]

6.94 = [6.02A% + 702 - 7.02A%] / 100

Cross multiply

6.02A% + 702 - 7.02A% = 6.94 × 100

6.02A% + 702 - 7.02A% = 694

Collect like terms

6.02A% - 7.02A% = 694 - 702

-A% = -8

A% = 8%

Thus,

Abundance of B = (100 - A)%

Abundance of B = (100 - 8)%

Abundance of B = 92%

SUMMARY

  • Abundance of A (Li6) = 8%
  • Abundance of B (Li7) = 92%

From the above, isotope Li7 is more abundant.

Learn more about isotope:

brainly.com/question/24311846

#SPJ1

4 0
2 years ago
Write the formula for Zn+2 (SO4)-2
Pie

Answer:

Zn2 + SO4 = Zn2(SO4)2

Explanation:

4 0
3 years ago
How does elements and compounds reacting together is essential in everyday matters?
MrMuchimi

Chemical reactions are at the essence of just about every biological and physical process in the whole universe. Stars form due to chemical reactions, our sun flamed up also because of chemical reactions in its core. Life basically evolved on Earth as an outcome of chemical reactions. The "circle of life" is, at its quintessence, a sequence of chemical reactions. Also our capacity to move and think  is an outcome of chemical reactions that happen inside our bodies. Chemical reactions are the reason why new forms of matter are created. Chemical reactions make us comprehend the properties of matter. Chemical reactions make food into fuel for our bodies, they make fireworks blow up, they change food when it is cooked, they make soap remove dirt, and a lot more. Chemical reactions contribute to solving crimes and unravel mysteries. We can even find out which planets and moons are most likely to be able to preserve life. The most significant and momentous discovery made by humans, fire, is just a chemical reaction. Nothing would ever change without chemical reactions

3 0
3 years ago
For the reaction 2Co3+(aq)+2Cl−(aq)→2Co2+(aq)+Cl2(g). E∘=0.483 V what is the cell potential at 25 ∘C if the concentrations are [
sveta [45]

Explanation:

The given data is as follows.

     E^{o} = 0.483,     [Co^{3+}] = 0.173 M,

     [Co^{2+}] = 0.433 M,     [Cl^{-}] = 0.306 M,

     P_{Cl_{2}} = 9.0 atm

According to the ideal gas equation, PV = nRT

or,             P = \frac{n}{V}RT    

Also, we know that

                Density = \frac{mass}{volume}

So,         P = MRT

and,          M = \frac{P}{RT}

                    = \frac{9.0 atm}{0.0820 L atm/mol K \times 298 K}

                    = \frac{9.0}{24.436}

                    = 0.368 mol/L

Now, we will calculate the cell potential as follows.

          E = E^{o} - \frac{0.0591}{n} log \frac{[Co^{2+}]^{2}[Cl_{2}]}{[Co^{3+}][Cl^{-}]^{2}}

             = 0.483 - \frac{0.0591}{2} log \frac{(0.433)^{2}(0.368)}{(0.173)(0.306)^{2}}

             = 0.483 - 0.02955 log \frac{0.0689}{0.0162}

             = 0.483 - 0.02955 \times 0.628

             =  0.483 - 0.0185

             = 0.4645 V

Thus, we can conclude that the cell potential of given cell at 25^{o}C is 0.4645 V.

4 0
4 years ago
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