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Allushta [10]
3 years ago
12

Describe how the freeze-thaw cycle of ice will change the shape of this rock over time. PLSSSS HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!

!!!!!!!!!!!!✋
Chemistry
2 answers:
Ludmilka [50]3 years ago
6 0

Freeze-Thaw Weathering

This action can widen the cracks in the rock, and when the temperature rises above freezing, the ice thaws, allowing the water to seep further into the cracks. As this process of freezing and thawing happens repeatedly, the rock begins to weaken and eventually breaks apart into angular fragments.

Reptile [31]3 years ago
6 0

Answer:

Physical weathering is caused by the effects of changing temperature on rocks, causing the rock to break apart. The process is sometimes assisted by water. ... Freeze-thaw occurs when water continually seeps into cracks, freezes and expands, eventually breaking the rock apart.

Explanation:

hope this helps

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A weather balloon is filled with helium that occupies a volume of 3.93 104 L at 0.995 atm and 32.0°C. After it is released, it r
user100 [1]

Answer: Thus the volume of the balloon at that new location is 4.65\times 10^4L

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.995 atm

P_2 = final pressure of gas = 0.720 atm

V_1 = initial volume of gas = 3.93\times 10^4L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 32.0^oC=273+32.0=305.0K

T_2 = final temperature of gas = -11.7^oC=273-11.7=261.3K

Now put all the given values in the above equation, we get:

\frac{0.995\times 3.93\times 10^4}{305.0}=\frac{0.720\times V_2}{261.3}

V_2=4.65\times 10^4L

Thus the volume of the balloon at that new location is 4.65\times 10^4L

4 0
3 years ago
Determine the mass in grams of 3.75 x 10^21 atoms of zinc. (the mass of one mole of zinc is 65.39 g)
Nastasia [14]

Answer: The mass in 3.75 \times 10^{21} atoms of zinc is 0.405 g.

Explanation:

Given: Atoms of zinc = 3.75 \times 10^{21}

It is known that 1 mole of every substance contains 6.022 \times 10^{23} atoms. So, the number of moles in given number of atoms is as follows.

Moles = \frac{3.75 \times 10^{21}}{6.022 \times 10^{23}}\\= 0.622 \times 10^{-2}\\= 0.0062 mol

As moles is the mass of a substance divided by its molar mass. So, mass of zinc (molar mass = 65.39 g/mol) is calculated as follows.

Moles = \frac{mass}{molar mass}\\0.0062 mol = \frac{mass}{65.39 g}\\mass = 0.405 g

Thus, we can conclude that the mass in 3.75 \times 10^{21} atoms of zinc is 0.405 g.

6 0
3 years ago
If the Earth had no tilt, how would that affect our seasons? I will give branliest to first comment
Aleks [24]

Answer:

in my opinion it wouldn't be regular seasons like what we have now it would be equal in every poles .. there would not be ice in North. [its my opinion though] sorry if I am wrong

6 0
3 years ago
One gram of liquid benzene is burned in a bomb calorimeter. The temperature before ignition was 20.826 ℃, and the temperature af
gtnhenbr [62]

Answer:fH = - 3,255.7 kJ/mol

Explanation:Because the bomb calorimeter is adiabatic (q =0), there'is no heat inside or outside it, so the heat flow from the combustion plus the heat flow of the system (bomb, water, and the contents) must be 0.

Qsystem + Qcombustion = 0

Qsystem = heat capacity*ΔT

10000*(25.000 - 20.826) + Qc = 0

Qcombustion = - 41,740 J = - 41.74 kJ

So, the enthaply of formation of benzene (fH) at 298.15 K (25.000 ºC) is the heat of the combustion, divided by the number of moles of it. The molar mass od benzene is: 6x12 g/mol of C + 6x1 g/mol of H = 78 g/mol, and:

n = mass/molar mass = 1/ 78

n = 0.01282 mol

fH = -41.74/0.01282

fH = - 3,255.7 kJ/mol

4 0
3 years ago
Just take it for free,
Orlov [11]

Answer:

Thanks bro, I will gladly take them for free

5 0
3 years ago
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