Answer:
on the grap x,y by using graph tranformation
Answer:
The area of the logo is 
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
The area of a semicircle is equal to

so
The area of the logo is equal to multiply by 3 the area of one semicircle

we have
-----> the radius is half the diameter
substitute

1.30 represents the rate of growth of the mold spores. This decimal is a representation of the percentage growth, which would be 130%.
Since the function is written in terms of weeks, x will equal 4 to represent the amount of spores after 4 weeks. Plug the value into the function:

Rounded to the nearest ones value, there will be 985 mold spores after 4 weeks.
Answer:
ANGLE K IS 75 DEGREES
All the interior angles of a triangle ADD up to 180 degrees
lets add the angles!
6x-11+8x-29+3x-1
add like terms. all the x terms add up and all the constants as well
8x+6x+3x = 17x
-29-1-11 = -41
17x-41= 180 (-41 + 41 = 0 we do this to remove -41 from the left side of the equation to isolate x)
41+180 = 221
17x=221
221/17 = 13
x=13
so..
8 * 13 - 29 is the angle..
8*13 = 104
and 104-29 = 75
Angle K is 75 degrees! hope that helps..
Step-by-step explanation:
Answer:
0.75 ft/min
Step-by-step explanation:
Given;
Length of trough l = 8 ft
base length of trough b = 3 ft
height of trough h = 1 ft
Change in volume dV/dt = 12 ft^3/min
At height hi = 8 in = 2/3 ft
Ratio of base to height;
b/h = 3/1
b = 3h .....1
The volume of the trough;
V = area of triangle × length
V = 1/2 × b×h × l
V = 1/2(bhl) .....2
Substituting l = 8ft and equation 1 (b = 3h) into equation 2;
V = 1/2(3h × h × 8)
V = 12h^2
differentiating V, change in volume per time is;
dV/dt = 12 × 2h .dh/dt
dV/dt = 24 hi .dh/dt
Substituting the values of dV/dt and hi;
12 = 24(2/3) .dh/dt
dh/dt = 12 ÷ 24(2/3) = 12/16
dh/dt = 3/4 ft/min = 0.75 ft/min