Answer:
The initial value is the y value when x is zero. Look at the table to help you determine the y value when x is zero and that is your answer.
Step-by-step explanation:
Step-by-step explanation:
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f(g(x))=362−x−2k f(g(x))=x→362−x−2k=x→x2−2x(1−k)−4(k−9)=0 Solution for x are equal if and only if discriminant Δ=0 4(1−k)2+16(k−9)=0 ... More
132.55=5(.04m+2+.7+0.1(21.7))>>>m=66
