Answer:
a) The equation is:
Confidence Interval = Mean ± Z score × Standard deviation/√Number of samples
b) The 98% confidence interval = (5.62784, 6.37216)
Step-by-step explanation:
a. Write down the equation you should use to construct the confidence interval for the average number of days absent per term for all the children. (10 points)
Confidence Interval = Mean ± Z score × Standard deviation/√Number of samples
b. Determine a 98% confidence interval estimate for the average number of days absent per term for all the children. (10 points)
Confidence Interval = Mean ± Z score × Standard deviation/√Number of samples
Mean = 6 days
Standard deviation = 1.6 days
Number of samples = 100
Z score of 98% confidence interval = 2.326
Confidence interval = 6 ± 2.326 × 1.6/√100
= 6 ± 2.326 × 1.6/10
= 6 ± 0.37216
= 6 - 0.37216
= 5.62784
6 + 0.37216
= 6.37216
Therefore, the 98% confidence interval = (5.62784, 6.37216)
Answer:
<u>x</u><u> </u><u>is</u><u> </u><u>2</u><u>8</u><u>°</u>
Step-by-step explanation:
Alternate angles of parallel lines:
-20% + 10 % = -10%
The ticket was less by 10 percent.
Answer:
210
Step-by-step explanation:
double negatives = positive
-7 * -6 * 5 = 7 * 6 * 5 = 42* 5 = 210
Answer:
the answer iissss.....5x-15
