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m_a_m_a [10]
3 years ago
5

The art teacher bought 1,500 beads for a new art project. 25% of the beads are red, 35% of the beads are green, the rest of the

beads are blue. How many beads are blue?
Mathematics
1 answer:
Pavlova-9 [17]3 years ago
5 0
40% or 600.

1500 x .4
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VikaD [51]
Just multiply the fractions by 32
3 0
3 years ago
Solve for y z= x+y/5 due in 9 mins
Makovka662 [10]

Answer:

y = 5z - x

Step-by-step explanation:

Given

z = \frac{x+y}{5} ( multiply both sides by 5 to clear the fraction )

5z = x + y ( subtract x from both sides )

5z - x = y

7 0
3 years ago
F(x)= 1/2x^2-4x+3 in standard form
Finger [1]

Answer:

Already in standard form

Step-by-step explanation:

A quadratic equations standard form is ax^2 + bx + c. This equation is already in standard form.

ax^2 + bx + c

1/2 x^2 - 4x + 3

5 0
3 years ago
Lucy has two star systems left to visit on her voyage, but her ship is running low on fuel. The first system, KA-77, is 12001200
-Dominant- [34]

Answer:

 1348 light years.    

Step-by-step explanation:

Please find the attachment.

Let x represent the distance between KA-7 and KA-11.

We have been given that the first system, KA-7, is 1200 light years away while the second system, KA-11, is 1700 light years away. Lucy sees an angle of 52 degrees between KA-7 and KA-11.

We can see from our attachment that Lucy, KA-7 and KA-11 forms a triangle and we will use law of cosines to solve for x.  

(AB)^2=(AC)^2+(BC)^2-2(AC)(BC)*cos (C)

Upon substituting our given values in above formula we will get,

x^2=1200^2+1700^2-2*1200*1700*cos (52^o)  

x^2=1440000+2890000-4080000*0.615661475

x^2=4330000-2511898.81933008

x^2=1818101.18066992

Let us take square root of both sides of our equation.

x=\sqrt{1818101.18066992}

x=1348.3698234\approx 1348

Therefore, KA-7 and KA-11 are approximately 1348 light years apart.

6 0
3 years ago
Can someone help me with this it is confusing :(
Marina CMI [18]
What are you wanting help with
7 0
3 years ago
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