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klio [65]
3 years ago
13

Choose the solution to this inequality.

Mathematics
1 answer:
torisob [31]3 years ago
3 0

Answer:

the answer is B

Step-by-step explanation:

you subtract 9/5 on both sides, find the common denominator which in this case would be 10. so 35-18 is 17. turn that into a mixed fraction and you get 1 and 7/10

You might be interested in
If 90 percent of a is 44, what is 30 percent of 3a?
Lesechka [4]
90% of "a" is 44.......turn ur percent into a decimal...." of " means multiply..." is " means equals...

0.90a = 44...divide both sides by 0.90
a = 44 / 0.90
a = 48.89.....this is rounded

what is 30% of 3a.....and we know that "a" is 48.89...

0.30(3 * 48.89) = 0.30(146.67) = 44 <=== ur answer
3 0
4 years ago
A small jet can carry up to 44 passengers and 3 crew members. There is a weight restriction of 9200 pounds on board. The combine
Agata [3.3K]

Answer:

2.89 percent chance

Step-by-step explanation:

so first if you divide 9200 and 47 you get a total of 195.74 .now if you combine the weight of each passenger and crew memeber and their luggage it has a mean of 200.4 pounds with a standard deviation of 69.3 pounds  so their is a 2.89 percent chance im sure if not shoe me the nswers and i will give you th correct answer

7 0
4 years ago
What is the mean for this list of numbers? 19, 22, 24, 45
STALIN [3.7K]

Answer:

27.5

Step-by-step explanation:

To find the mean you basically just add all of the numbers then divide by how many there are.

So, for this problem, 19+22+24+45=110

110/4=27.5

Hope this helped!!

5 0
3 years ago
The sum of four consecutive odd integers is three more than five times the least of the integers. Find the integers.
Olegator [25]

Answer:

<h3>              9, 11, 13, 15</h3>

Step-by-step explanation:

{k - some integer}

2k+1  - the first odd integer (the least)

5(2k+1)  - five times the least

5(2k+1)+3 -<u> three more than five times the least</u>

2k+1+2 = 2k+3  - the odd integer consecutive to 2k+1

2k+3+2 = 2k+5  - the next odd consecutive integer (third)

2k+5+2 = 2k+7  - the last odd consecutive integer (fourth)

2k+1+2k+3+2k+5+2k+7 - <u>the sum of four odd consecutive integers</u>

2k+1 + 2k+3 + 2k+5 + 2k+7 = 5(2k+1) + 3

8k + 16 = 10k + 5 + 3

     - 10k       -10k

-2k + 16 = 8

     -16       - 16    

      -2k = -8  

    ÷(-2)    ÷(-2)  

      k = 4

2k+1 = 2•4+1 = 9

2k+3 = 2•4+3 = 11

2k+5 = 2•4+5 = 13

2k+7 = 2•4+7 = 15  

Check: 9+11+13+15 = 48;  48-3 = 45;  45:5 = 9 = 2k+1

4 0
3 years ago
Eight workers are hired to harvest strawberries from a field.Each is given a plot which is 9*6 feet in size. What is the total a
GrogVix [38]
Since the equations for area is A= L*W 

A= 9*4= 54
3 0
4 years ago
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