Answer:
it does have a solution x=0
Step-by-step explanation:
9x+15=3x+15
6x+15=15
6x=0
x=0
Shifts:
Shifted three units right and two units up to match the blue parabola
Stretches:
It doesn't have any stretches
Symmetry:

x and y intercepts:
x intercpets: It has no x-intercepts
y-intercepts: (0, 11)
<h2>
Explanation:</h2>
The pattern of the quadratic function is:

Whose graph is shown below as the red parabola.
So here we need to identify some characteristics of:

Whose graph is shown below as the blue parabola.
As you can see, the blue parabola is a transformation of the red parabola. The rule is as follows:
- The red parabola has been shifted three units right and two units up to match the blue parabola.
This is so because, for any function:

We have the following transformations:

On the other hand, the blue graph has neither stretches nor x intercepts. Finally, its axes of symmetry is
. The y-intercept is (0, 11) is indicated in the figure.
<h2>Learn more:</h2>
Shifting graphs: brainly.com/question/10010217
#LearnWithBrainly
Answer:
the answer is (x – 4)(x2 + 4x + 16).
The answer is either B or D
Note that the 2nd equation can be re-written as y=8x-10.
According to the second equation, y=x^2+12x+30.
Equate these two equations to eliminate y:
8x-10 = x^2+12x+30
Group all terms together on the right side. To do this, add -8x+10 to both sides. Then 0 = x^2 +4x +40. You must now solve this quadratic equation for x, if possible. I found that this equation has NO REAL SOLUTIONS, so we must conclude that the given system of equations has NO REAL SOLUTIONS.
If you have a graphing calculator, please graph 8x-10 and x^2+12x+30 on the same screen. You will see two separate graphs that do NOT intersect. This is another way in which to see / conclude that there is NO REAL SOLUTION to this system of equations.