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dybincka [34]
4 years ago
15

If jerry had 4 apples 65 weeks later how many apples would he have

Mathematics
1 answer:
iVinArrow [24]4 years ago
7 0
4x65=260 jerry would have 260 apples in 65 weeks.
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The graph below shows the amount of money left in the school’s desk fund, f, after d desks have been purchased. A graph titled D
natima [27]

Answer:

$110

Step-by-step explanation:

The computation is shown below:

Provided that

Number of desk purchased    Fund Left $

           0                                   700

           1                                    590

           2                                   480

           3                                   370

           4                                   260

           5                                   150

           6                                    40

Now the Fund decreased while purchasing is

= 5 desks - 2 desks

= 3 desks

i.e

= $480 - $150

= $330

Now the amount of money left for decreased the desk fund is

= \frac{Fund\ decreased }{number\ of\ desk\ decreased}

= \frac{\$330}{3\ desk}

= $110

3 0
3 years ago
Read 2 more answers
Use the number line below, where RS = 9y +3, ST = 3y + 4, and RT = 17y - 33.
zavuch27 [327]

Answer:

R___S___T

RT=RS+ST

(17y-33) =( 9y+3)+(3y+4)

17y-33 = 12y+ 7

17y - 12y = 7+33

5y= 40

y=40/5

y= 8

RS = 9y+3 = 9(8)+3= 72+3=75

ST= 3y+4 = 3(8)+4=24+4=28

RT= 17y-33= 17(8)-33= 136-33= 103 —>

<u>Or</u><u> </u><u>;</u> RT=RS+ST =75+28= 103

<h3><u>So</u><u>;</u></h3><h3>a. <u>Ans;</u> y=8</h3>

<h3>b. <u>Ans;</u> RS= 75 , ST = 28 , RT = 103</h3>

I hope I helped you^_^

4 0
3 years ago
At the local grocery store,a 16- ounce bottle of apple juice cost $3.20.What is the cost of the apple juice per ounce?
choli [55]
It would be 20¢ per ounce
3 0
4 years ago
Read 2 more answers
A college student organization wants to start a nightclub for students under the age of 21. To assess support for this proposal,
eduard

Answer:

a) Sample size = 822

b) Margin of error = 0.03407          

Step-by-step explanation:

We are given the following in the question:

p = 74% = 0.74

a) Sample size is required to obtain margin of error of 0.03

Formula:

\text{Margin of error} = z_{\text{statistic}}\times \sqrt{\dfrac{p(1-p)}{n}}}

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

Putting values, we get,

0.03 = 1.96\times \sqrt{\dfrac{0.74(1-0.74)}{n}}\\\\n = (\dfrac{1.96}{0.03})^2(0.74)(1-0.74)\\\\n = 821.24 \approx 822

Thus, the sample size must be approximately 822  to obtain a 95% confidence interval with an approximate margin of error of 0.03

b) Margin of error for the 95% confidence interval

p = 54% = 0.54

Formula:

\text{Margin of error} = z_{\text{statistic}}\times \sqrt{\dfrac{p(1-p)}{n}}}

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

Putting values, we get,

\text{Margin of error} = 1.96\times \sqrt{\dfrac{0.54(1-0.54)}{822}}\\\\=0.03407

The margin of error now will be 0.03407.

5 0
4 years ago
Add (-2x+4)+(4x+6) evaluate this equation
Viefleur [7K]

Answer:

2x + 10

Step-by-step explanation:

3 0
3 years ago
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