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3 years ago

If n/5=45/75.find the value of n.

Mathematics

2 answers:

julsineya [31]3 years ago

4 0

Answer:

n = $\frac{9}{5}$

Step-by-step explanation:

Simplify the fraction on the right side

$\frac{n}{5}$ = $\frac{45}{75}$ = $\frac{3}{5}$ ( cross- multiply )

5n = 15 ( divide both sides by 5 )

n = 3

Stells [14]3 years ago

3 0

Start with

$\dfrac{n}{5}=\dfrac{45}{75}$

Multiply both sides by 5:

$n = \dfrac{45\cdot 5}{75} = \dfrac{45}{15} = 3$

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Find the derivative of the function f(x) = (x3 - 2x + 1)(x – 3) using the product rule.

julsineya [31]

Answer:

Step-by-step explanation:

Hello, first, let's use the product rule.

Derivative of uv is u'v + u v', so it gives:

$f(x)=(x^3-2x+1)(x-3)=u(x) \cdot v(x)\\\\f'(x)=u'(x)v(x)+u(x)v'(x)\\\\ \text{ **** } u(x)=x^3-2x+1 \ \ \ so \ \ \ u'(x)=3x^2-2\\\\\text{ **** } v(x)=x-3 \ \ \ so \ \ \ v'(x)=1\\\\f'(x)=(3x^2-2)(x-3)+(x^3-2x+1)(1)\\\\f'(x)=3x^3-9x^2-2x+6 + x^3-2x+1\\\\\boxed{f'(x)=4x^3-9x^2-4x+7}$

Now, we distribute the expression of f(x) and find the derivative afterwards.

$f(x)=(x^3-2x+1)(x-3)\\\\=x^4-2x^2+x-3x^3+6x-4\\\\=x^4-3x^3-2x^2+7x-4 \ \ \ so\\ \\\boxed{f'(x)=4x^3-9x^2-4x+7}$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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3 years ago

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AVprozaik [17]

Answer:

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Step-by-step explanation:

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LiRa [457]

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