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3 years ago

When is estimation an effective way to determine an answer?

2 answers:

8 0

Answers that are way off the answer you came up with can automatically be eliminated because those are most likely trick answers people can fall for. Rounding or estimating can ensure your answer by a slight chance.

Elden [556K]3 years ago

7 0

The answer above is not going to get you anywhere.

Most of the time you should estimate when you have a long decimal.

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Among a group of 100 people, 68 can speak English, 45 can speak French, 42 can speak Spanish. 27 can speak both English and Fren

Nat2105 [25]

Answer:

Step-by-step explanation:

Given

No of People who can speak English is $n(E)=68$

No of People who can speak French is $n(F)=45$

No of People who can speak Spanish is $n(S)=42$

No of People who can speak both English and French $n\left ( E\cap F\right )=27$

No of People who can speak both English and Spanish $n\left ( E\cap S\right )=25$

No of People who can speak both French and Spanish $n\left ( F\cap S\right )=16$

No of people who can speak all languages is $n\left ( E\cap F\cap S\right )=9$

no of People who can Speak at least one Language is

$n\left ( E\cup F\cup S\right )=n\left ( E\right )+n\left ( F\right )+n\left ( S\right )-n\left ( E\cap F\right )-n\left ( E\cap S\right )-n\left ( F\cap S\right )+n\left ( E\cap F\cap S\right )$

$n\left ( E\cup F\cup S\right )=68+45+42-27-25-16+9=96$

Probability that Randomly selected can speak at least 1 of these languages

$P=\frac{96}{100}=0.96$

8 0

3 years ago

What’s the lcm of 24 &8 ?

LenaWriter [7]

The answer is 24 The multiples of 8 is 8 16 24..... the multiples of 24 48 72..... so therefore the answer is 24 make me the brainest

6 0

3 years ago

A number plus 5 is less than nine.<br><br>show work for this

Dimas [21]

Answer: x + 5 < 9

Step-by-step explanation:

A number: you can use any variable, such as an x.

Plus 5: plus means "+" and 5 is obviously 5.

Less than nine: less than means the number you wrote before has to be less than 9. You can use the "<" symbol for any equations that say "less than."

3 0

3 years ago

Factoring GCF<br> c^4d^2+c^2d^3

mr Goodwill [35]

Answer:

$c^2d^2(c^2 + d)$

Step-by-step explanation:

The equation is $c^4d^2 + c^2d^3$ so we see that the highest number on both terms that we can factor out is 2. If we factor out $c^2d^2$ from both terms, we end up with $c^2d^2(c^2 + d)$ , making $c^2d^2$ the GCF of this expression.

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3 years ago

Pleas help I’ll give u points

anastassius [24]

Step-by-step explanation:

5 0

3 years ago

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