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ratelena [41]
3 years ago
6

How can you use properties to solve 4×23×28

Mathematics
1 answer:
Kazeer [188]3 years ago
8 0
Multiply four and twenty three and then multiply the product by twenty eight and your answer will be thousand five hundred and seventy six.
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Which line is perpendicular to a line that has a slope of 1/2?
Flura [38]

Answer:

HJ

Step-by-step explanation:

For a line to be perpendicular to another line, you must find the negative reciprocal.

The negative reciprocal of 1/2 is -2.

The only line with a slope of -2 is line HJ because it goes down 2 for every 1 to the right.

8 0
3 years ago
Solve 5x - 13<br><br><br> Pls do not copy and paste
kipiarov [429]

Answer:

is -65

Step-by-step explanation:

4 0
3 years ago
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The distance around a circular lampshade is 219.8 mm. If Gail measures straight across the center of the lampshade from one side
fredd [130]

Answer: Longest distance  she could measure is 70 mm


Step-by-step explanation:

To find the longest distance from one side to other across the center we have to find the diameter of the lampshade.

As it is given that the distance around the lampshade is 219.8 mm which is equal to the circumference of the lampshade.


Circumference of the lampshade is = πD, where D is the diameter of the lampshade

219.8= 3.14D where the value of π=3.14

Divide both sides by 3.14 we get

\frac{219.8}{3.14} = D

on solving we get

D = 70

5 0
3 years ago
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#2 <br> #3 <br> Need help for my discrete math class
miss Akunina [59]

For (2), start with the base case. When n = 2, we have

(n + 1)! = (2 + 1)! = 3! = 6

2ⁿ = 2² = 4

6 > 4, so the case of n = 2 is true.

Now assume the inequality holds for n = k, so that

(k + 1)! > 2ᵏ

Under this hypothesis, we want to show the inequality holds for n = k + 1. By definition of factorial, we have

((k + 1) + 1)! = (k + 2)! = (k + 2) (k + 1)!

Then by our hypothesis,

(k + 2) (k + 1)! > (k + 2) 2ᵏ = k•2ᵏ + 2ᵏ⁺¹

and k•2ᵏ ≥ 2•2² = 8, so

k•2ᵏ + 2ᵏ⁺¹ ≥ 8 + 2ᵏ⁺¹ > 2ᵏ⁺¹

which proves the claim.

Unfortunately, I can't help you with (3). Sorry!

3 0
3 years ago
Reflected images are congruent to their pre-image true or false
gregori [183]
It's true......................................

4 0
3 years ago
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