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3 years ago

If the average grade of an English class rose from 70 to 85, what is the approximate percent increase?

Mathematics

2 answers:

Basile [38]3 years ago

4 0

85 - 70 = 15

15/70 = 0.21428571428

Round to .21

Move decimal over twice to the right

21%

wariber [46]3 years ago

3 0

Answer:

The percent increase is 21%.

Step-by-step explanation:

Given,

The original average grade = 70,

New average grade = 85,

Total changes in the average grade = New average grade - original average grade

= 85 - 70

= 15

Since,

$\text{The percentage increment in the grade}=\frac{\text{Total changes}}{\text{Original grade}}\times 100$

$=\frac{15}{70}\times 100$

$=\frac{1500}{70}$

$=21.4285714\approx 21\%$

⇒ The approximate percent increase is 21 %.

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Answer: There were 40 euros in the drawer at the beginning.

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When we subtract 6 from 16, we get 10 more ice-creams were sold.

Similarly, we subtract 70 from 120, we get 50 euros was the total selling price of 10 ice-creams.

i.e. Selling price of 1 ice-cream = (50)÷10 =5 euros

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3 years ago

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3 years ago

Select the correct answer.

garri49 [273]

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2 years ago

The radius of the base of a cylinder is increasing at a rate of 7 millimeters per hour. The height of the cylinder is fixed at 1

Ilya [14]

Answer:

The rate of change of the volume of the cylinder at that instant = $791.28\ mm^3/hr$

Step-by-step explanation:

Given:

Rate of increase of base of radius of base of cylinder = 7 mm/hr

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Radius at a certain instant = 12 mm

To find rate of change of volume of cylinder at that instant.

Solution:

Let $r$ represent radius of base of cylinder at any instant.

Rate of increase of base of radius of base of cylinder can be given as:

$\frac{dr}{dt}=7\ mm/hr$

Volume of cylinder is given by:

$V=\pi\ r^2h$

Finding derivative of the Volume with respect to time.

$\frac{dV}{dt}=\pi\ h\ 2r\frac{dr}{dt}$

Plugging in the values given:

$\frac{dV}{dt}=\pi\ (1.5)\ 2(12)(7)$

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Using $\pi=3.14$

$\frac{dV}{dt}=252(3.14)$

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Thus rate of change of the volume of the cylinder at that instant = $791.28\ mm^3/hr$

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