Answer:
The resultant of two forces of 7N and 3N acting at a right angle to one another is √58 N.
Step-by-step explanation:
Let the magnitude of the force of 7N be denoted as “F₁” on the x-axis and the magnitude of the force of 3N be denoted as “F₂” on the y-axis.
We are given that the two forces make an angle of 90° to one another as shown in the figure attached below.
Also, in the figure, we can see that the resultant force is denoted as “F”.
Now,
The magnitude of the resultant force can be calculated by using the Pythagoras theorem,
∴ F = √[F₁² + F₂²]
⇒ F = √[7² + 3²]
⇒ F = √[49 + 9]
⇒ F = √[58] N
Check the picture below.
the quadrilateral is a parallelogram, thus the diagonals bisect each other, so, we could have used either diagonal, and get the same midpoint.
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Answer:
2,827.43
Step-by-step explanation:
If you are solving for the question in the picture your answer would be 18. Whiich is letter A.
12x+15y=390 Original Equation
12(10)+15y=390 Replace x with 10
120 + 15y= 390 Mutiply 12 by 10
-120 = -120 subtract 120 on both sides to simplfy the equation
15y= 270 New equation
÷15 = ÷15 To get the variable alone divide 15 on both sides
y=18 Your value for y.
