According to Sturge's rule, number of classes or bins recommended to construct a frequency distribution is k ≈ 7
Sturge's Rule: There are no hard and fast guidelines for the size of a class interval or bin when building a frequency distribution table. However, Sturge's rule offers advice on how many intervals one can make if one is genuinely unable to choose a class width. Sturge's rule advises that the class interval number be for a set of n observations.
Given,
n = 66
We know that,
According to Sturge's rule, the optimal number of class intervals can be determined by using the equation:

Here, n is equal to 66 and by substituting the value to the equation we get:

k = 7.0444
k ≈ 7
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Answer:
The answer is 62.17
Step-by-step explanation:
Because 3 in the thousandths is not equal to or greater than 5
Answer: The correct answer is Choice B.
To factor this expression, we should first factor out the variable x.
We will have:
x(x^2 + 4x - 5)
Now, all we have to do is factor x^2 + 4x - 5.
The factors of this are (x + 5)(x - 1).
If you put all of the factors together, you have: x(x + 5)(x - 1) or Choice B.
Answer:
It is a polynomial of doom. mwahahahah, you cant stop me spider man
Step-by-step explanation:
Answer:
3.6 m
Step-by-step explanation:
Given that :
Length of room = 6
Distance between opposite corners = 7
Width of room :
Using Pythagoras rule:
Opposite ²= hypotenus² + adjacent²
From. The diagram attached :
w² = 7² - 6²
w² = 49 - 36
w² = 13
w = 3.605
w = 3.6 m