2sin²(-2490)+tan 1410=2sin²(-330-6*360)+tan (330+3*360)=
=2sin²(-330)+tan (330)=2 sin²(30-1*360)+tan (-30)=
=2sin²(30)-tan (30)=2(1/2)²-√3/3=1/2-√3/3)=(3-2√3)/6
Answer: 2 sin²(-2490)+tan (1410)=(3-2√3)/6 (≈-0.07735...)
Answer:
284.625
Step-by-step explanation:
Arrange the numbers highest to lowest.
Find the middle value in the arrangement.
8/10 is the answer to this problem
7 - 5 x m
-4 x 3
i believe these are correct if this isnt is there any other information?
