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3 years ago

when 9 is subtracted from the square of a number, the result is 8 times the number.Find the negative soulution.

Mathematics

2 answers:

Fed [463]3 years ago

7 0

The negative solution to this question is -3

Ne4ueva [31]3 years ago

5 0

the real answer is -2 don’t listen to these other mans

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Solve for x 4(2x+9)=-44+8

Andreas93 [3]

Answer:

x=-9

Step-by-step explanation:

distribute 4 into the parentheses

8x+36=-44+8

add -44+8

and u get 8x+36=-36

subtract the 36 on both sides and leave u with

8x=-72

divide 8 on both sides

and ur answer is -9

i dont think this make sense but hope this helps

5 0

3 years ago

Read 2 more answers

Write .125 as a fractionreduced to lowest terms.

horrorfan [7]

The Solution:

We are given the decimal below:

$\begin{gathered} .125 \\ \text{Which also means} \\ 0.125 \end{gathered}$

We are asked to express the given decimal as a fraction in its lowest term.

$0.125=\frac{125}{1000}=\frac{25}{200}=\frac{5}{40}=\frac{1}{8}$

Therefore,

7 0

1 year ago

2.3 to 1 significant figure

azamat

☽------------❀-------------☾

Hi there!

~

2.3 to 1 significant figure.

= 2

❀Hope this helped you!❀

☽------------❀-------------☾

3 0

3 years ago

Read 2 more answers

Find all solutions to x³+3x² − 9x − 27 = 0 by factoring the equation.

SCORPION-xisa [38]

Answer:

The solutions are $x=-3,\:x=3$

Step-by-step explanation:

To factor this cubic polynomial $x^3+3x^2-9x-27$ you must:

Group the polynomial into two sections

$x^3+3x^2-9x-27=\left(x^3+3x^2\right)+\left(-9x-27\right)$

Factor out -9 from $(-9x-27)$

$(-9x-27)=-9\left(x+3\right)$

Factor out $x^2$ from $(x^3+3x^2)$

$(x^3+3x^2)=x^2\left(x+3\right)$

$x^3+3x^2-9x-27=-9\left(x+3\right)+x^2\left(x+3\right)$

Factor out common term $x+3$

$-9\left(x+3\right)+x^2\left(x+3\right)=\left(x+3\right)\left(x^2-9\right)$

$x^3+3x^2-9x-27=\left(x+3\right)\left(x^2-9\right)$

Factor $x^2-9$

$x^2-9=\left(x+3\right)\left(x-3\right)$

$x^3+3x^2-9x-27= \left(x+3\right)\left(x+3\right)\left(x-3\right)$

$x^3+3x^2-9x-27=\left(x+3\right)^2\left(x-3\right)=0$

Using the Zero Factor Theorem: = 0 if and only if = 0 or = 0

$x+3=0, \quad{x=-3}\\x-3=0, \quad{x=3}$

The solutions are

$x=-3,\:x=3$

3 0

3 years ago

The polynomial p(x) = –2x3 + 3x + 4 is given. Which conclusion is valid if P(1) = 5?

Airida [17]

I think it’s A I hope it helps

8 0

3 years ago