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azamat
3 years ago
5

when 9 is subtracted from the square of a number, the result is 8 times the number.Find the negative soulution.

Mathematics
2 answers:
Fed [463]3 years ago
7 0
The negative solution to this question is -3
Ne4ueva [31]3 years ago
5 0

the real answer is -2 don’t listen to these other mans

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Find all real solutions of the equation by completing the square. (Enter your answers as a comma-separated list.) x2 − 4x − 8 =
Nat2105 [25]

Answer:

After completing the square the expression is (x-2)^2 -12 =0 and real solution are x = 5.46 and x = -1.46

Step-by-step explanation:

We need to complete the square:

x^2 − 4x − 8 = 0

x^2 -2(x)(2)+(2)^2 -8 -4 =0

(x^2 -4x +4) - 12 = 0

(x-2)^2 -12 =0

Now, finding the value of x

(x-2)^2 -12 =0

(x-2)^2 = 12

taking square root on both sides

\sqrt{(x-2)^2}= \sqrt{12} \\(x-2) = \pm\sqrt{12} \\x = \pm\sqrt{12} +2\\x = \sqrt{12}+2 \,\,and\,\,x=-\sqrt{12}+2\\x= 3.46+2 \,\,and\,\,x=-3.46+2\\x =5.46\,\,and\,\,x=-1.46

So, After completing the square the expression is (x-2)^2 -12 =0 and real solution are x = 5.46 and x = -1.46

5 0
3 years ago
Given the system
Irina-Kira [14]

we have

y > -2 x + y < 4

using a graph tool

see the attached figure

The shaded area is the solution of the system

<u>Part 1) </u>Name an ordered pair that is a solution to this system and explain how you know that this is a solution point

Let

A ( -40,20)

The point A is solution of the system because the point lie on the shaded area

<u>Check</u>

If the point A is solution of the system must satisfy both system inequalities

point A

x=-40

y=20

substitute

y > -2-------> 20 > -2-------> is ok

x + y < 4----> -40+20 < 4-----> -20 < 4-----> is ok

therefore

<u>the answer Part 1) is</u>

The point A is a solution of the system

Part 2) Name an ordered pair that is not a solution to the system and explain how you know that it is not a solution

Let

B(20,20)

The point B is not solution of the system because the point not lie on the shaded area

<u>Check</u>

If the point B is not solution of the system must not satisfy both system inequalities

point B

x=20

y=20

substitute

y > -2 -------> 20 > -2-------> is ok

x + y < 4---->20+20 < 4-----> 40 < 4------> is not ok

therefore

<u>the answer part 2) is</u>

The point B is not a solution to the system

6 0
3 years ago
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