Hi!
I’d use Pythagora’s theorem here. If PR is 6, PQ is also 6. PQO is a right angle.
OQ^2=6.8^2 - 6^2
OQ^2=46.24 - 36
OQ^2=10.24
OQ= sqrt 10.24
OQ=3.2
Solve (x+3) / 3x > 2 . [I guess 3x divides (x+3) and not 3], if so, then
(x+3) > 6x → 3 > 6x-x → OR x < 3/5 OR x<0.6
Answer:
75% of the households have between 2 and 6 televisions
Step-by-step explanation:
From the question, we can deduce the following;
sample size n= 8
sample mean μ = 4
standard deviation σ = 1
Using Chebychev’s theorem;
P(2 ≤ X ≤ 6) = P(2-4 ≤ (X - μ) ≤ 6-4)
= P(-2 ≤ (X-μ) ≤ 2) = P(|X-μ| ≤ kσ) ≥ (1 - 1/k^2) ≥ (1- 1/2^) = 1- 0.25 = 0.75 ( same as 75%)
<span>1C. 5^3 = 125 mL
2A. 30^3 = 27,000 mL = 27 L
3D. 75 mm is 7.5 cm, so we do: 7.5^3 = 421.875 mL = 0.421875 L =~ 0.422 L
Note:
1 mL = 1 cm^3
1 L = 1,000 mL
10 mm = 1 cm</span>
