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3 years ago

Help me with question 1 please!

Mathematics

1 answer:

muminat3 years ago

4 0

Answer:

3045 mi

Step-by-step explanation:

To find the perimeter, we need to add all 3 sides. Let x be the perimeter.

965+1038+1042=x

Add them up

3045=x

The perimeter is 3045 mi.

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Given: // CDAB , ∠≅∠ DB and ≅ EDBF . Prove: Δ ABF ≅ Δ CED

SCORPION-xisa [38]

Given: line segment AB // to line segment CD, ∠B ≅∠D and line segment BF ≅ to line segment ED. Prove: Δ ABF ≅ Δ CED.

Follow the matching numbers on the statement versus reason chart.

Statement:

1. line segment AB // to line segment CD.

2. ∠B ≅∠D

3. line segment BF ≅ to line segment ED.

4. ∠A ≅∠C

5. Δ ABF ≅ Δ CED

Reason:

1. Given

2. Given

3. Given

4. Alternate interior angles are congruent.

5. Corresponding parts of congruent triangles are congruent.

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3 years ago

Solve 73 make sure to also define the limits in the parts a and b

Aleks04 [339]

73.

$f(x)=\frac{3x^4+3x^3-36x^2}{x^4-25x^2+144}$

$\lim_{x\to\infty}f(x)=\lim_{x\to\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3$ $\lim_{x\to-\infty}f(x)=\lim_{x\to-\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3\cdot\frac{1}{2}=3$

Since we can't divide by zero, we need to find when:

$x^4-2x^2+144=0$

But before, we can factor the numerator and the denominator:

$\begin{gathered} \frac{3x^2(x^2+x-12)}{x^4-25x^2+144}=\frac{3x^2((x+4)(x-3))}{(x-3)(x-3)(x+4)(x+4)} \\ so: \\ \frac{3x^2}{(x+3)(x-4)} \end{gathered}$

Now, we can conclude that the vertical asymptotes are located at:

$\begin{gathered} (x+3)(x-4)=0 \\ so: \\ x=-3 \\ x=4 \end{gathered}$

so, for x = -3:

$\lim_{x\to-3^-}f(x)=\lim_{x\to-3^-}-\frac{162}{x^4-25x^2+144}=-162(-\infty)=\infty$ $\lim_{x\to-3^+}f(x)=\lim_{x\to-3^+}-\frac{162}{x^4-25x^2+144}=-162(\infty)=-\infty$

For x = 4:

$\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty$ $\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty$

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8 months ago

Ms. M feeds her fish 1/5 of food each day. There is 25 cups of cat food in the bag. How many days will the bag of cat food last?

Harlamova29_29 [7]

Answer is 5

first you do 1 divided by 5 then you times by 25

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2 years ago

Find the value of n <br><br> Thank you

melisa1 [442]

Answer:37

Step-by-step explanation:sorry if its worng

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2 years ago

The perimeter cf a rectangle i: 56 inches" the ratio of the length of the width is 6 : 1. Find the length and the width.

sergejj [24]

Answer: Length = 24; width =4

Step-by-step explanation

Since the ratio of the length to width is 6:1

Let the length be represented as 6x

And the width be = x

Such that that the Perimeter of the rectangle which is

Perimeter = 2(length + width) becomes

56 = 2(6x + x)

56/2 = 6x+x

28 = 7x

x = 4

Width = 4

Length = 6x= 6 x 4 = 24

8 0

2 years ago