This is a probablity question
there are 3 slots, 26 letters of the alphabet
so in the first slot, we have 26 possible letters
2nd slot, we have 25 possible letters (we used one for the first slot)
3rd slot, we have 24 possible letters, (we used 2 for first and 2nd slot)
so in total, we have 26*25*24 or 15600 different 3 letter initials with no repeated letters
Answer:
search up on google
Step-by-step explanation:
not hard
Answer:
<h2>
first piece: 5 in</h2><h2>
second piece: 10 in</h2><h2>
third piece: 32 in </h2>
Step-by-step explanation:
x - the length of the <u>first piec</u>e
2x - twice the length of the first piece (the length of the <u>second piece</u>)
6x - six times the length of the first piece
two inches more:
6x+2 - the length of the <u>third piec</u>e
first + second + third = 47 in {total length of the pieces of steel}
x + 2x + 6x + 2 = 47
9x + 2 = 47
9x = 45
x = 45:9
x = 5 in
first piece: 5 in
second piece: 2×5 = 10 in
third piece: 6×5 + 2 = 30 + 2 = 32 in
14, B. I hope that helps! :)
