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3 years ago

What is 10÷5×8 equals to

Mathematics

1 answer:

Kaylis [27]3 years ago

5 0

10/5 = 2

2 * 8 = 16

The correct answer is 16.

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Perform the indicated operation. (36m 2 - 60m + 25) ÷ (6m - 5)

9966 [12]

The correct answer for this is 6m - 5
That is the final expression.
Mark brainliest :)

6 0

2 years ago

Question is on picture Please help Zoom in if needed :D

Anastasy [175]

96$ source: just trust me bro

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2 years ago

The link of a garden is 125 of It’s with in the garden is 8 m what is the area of the garden.

NISA [10]

Answer

1000m^2

Step-by-step explanation:

125 * 8 = 1000m^2

6 0

2 years ago

Write an equation in slope-intercept form for the line that is parallel to y=−4x−3 and that passes through the point (−2,4).

kirill115 [55]

Answer:

The Correct option is Last one $y=-4x-4$

Therefore, equation of the line in slope-intercept that passes through (-2,4) and is parallel to the line $y=-4x-3$ is $y=-4x-4$

Step-by-step explanation:

Given:

$y=-4x-3$

To Find:

Equation of line passing through ( -2, 4) and is parallel to the line y=-4x-3

Solution:

$y=-4x-3$ ..........Given

Comparing with Slope-Intercept form,

$y=mx+c$

Where m =slope

We get

$Slope = m = -4$

We know that parallel lines have Equal slopes.

Therefore the slope of the required line passing through (-2 , 4) will also have the slope = m = -4.

Now the equation of line in slope point form given by

$(y-y_{1})=m(x-x_{1})$

Substituting the points and so we will get the required equation of the line,

$(y-4))=-4(x-(-2))=-4x-8\\\\y=-4x-8+4=-4x-4\\\\y=-4x-4......Equation\ of\ line$

Therefore, equation of the line in slope-intercept that passes through (-2,4) and is parallel to the line $y=-4x-3$ is $y=-4x-4$

8 0

2 years ago

The polygons are regular polygons. Find the area of the shaded region.

Serga [27]

Polygon area = [circumradius^2 * # sides * sine (360/# sides)] / 2
small hexagon area =[5^2 * 6 * sine (60)] / 2
small hexagon area =[25 * 6 * 0.86603] / 2
small hexagon area = 64.95225 sq feet

large hexagon area =[10^2 * 6 * sine (60)] / 2
large hexagon area =[600 * 0.86603] / 2large hexagon area = 259.809 sq feet
Area of shaded region = large hexagon area -small hexagon areaArea of shaded region = 259.809 -64.95225 Area of shaded region = 194.85675 sq feet

Source:http://www.1728.org/polygon.htm

6 0

2 years ago