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Ad libitum [116K]
3 years ago
8

6 pounds of strawberries cost $13.50. What is the cost of 50 pounds of strawberries?

Mathematics
1 answer:
Nitella [24]3 years ago
7 0

Answer:

$112.50

Step-by-step explanation:

13.50 / 6 = 2.25; this is how much it cost per pound

2.25 * 50 = 112.50

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In 2009, Jennifer made $11.50 an hour, and in 2010, she made $12.75 an hour. What is the percent of change in Jennifer’s pay per
Tanzania [10]

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10.9% Increase

Step-by-step explanation:

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3 years ago
WILL GIVE BRAINLIEST
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1. A sailboat heads west across a lake. It travels
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Answer:

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Step-by-step explanation:

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Read 2 more answers
Maureen McIlvoy, owner and CEO of a mail order business for wind surfing equipment and supplies, is reviewing the order filling
lara31 [8.8K]

Answer:

Maureen's null hypothesis is, <em>H₀</em>: <em>p</em>₁ ≥ <em>p</em>₂.

Step-by-step explanation:

Maureen McIlvoy, owner and CEO of a mail order business for wind surfing equipment and supplies wants test whether her goal of shipping 100% orders within 24 hours is achieved or not.

After reviewing the order filling operations at her warehouses she determines that neither the East coast nor the West coast warehouse has achieved the goal. But the East Coast warehouse has consistently out-performed the West Coast warehouse.

To check whether this determination is correct or not Maureen's staff randomly selected 200 orders from the West Coast warehouse (population 1) and 400 orders from the East Coast warehouse (population 2).

Of the 200 orders from the West Coast warehouse, 190 were shipped within 24 hours. And of the 400 orders from the East Coast warehouse, 372  were shipped within 24 hours.

The hypothesis can be defined as follows:

<em>H₀</em>: The proportion of orders that were shipped within 24 hours is not more for East Coast warehouse than for West Coast warehouse, i.e. <em>p</em>₁ ≥ <em>p</em>₂.

<em>Hₐ</em>: The proportion of orders that were shipped within 24 hours is more for East Coast warehouse than for West Coast warehouse, i.e. <em>p</em>₁ < <em>p</em>₂.

Thus, Maureen's null hypothesis is, <em>H₀</em>: <em>p</em>₁ ≥ <em>p</em>₂.

8 0
3 years ago
A circle is growing so that the radius is increasing at the rate of 3 cm/min. How fast is the area of the circle changing at the
Naya [18.7K]

Answer:

The area is growing at a rate of \frac{dA}{dt} =226.2 \,\frac{cm^2}{min}

Step-by-step explanation:

<em>Notice that this problem requires the use of implicit differentiation in related rates (some some calculus concepts to be understood), and not all middle school students cover such.</em>

We identify that the info given on the increasing rate of the circle's radius is 3 \frac{cm}{min} and we identify such as the following differential rate:

\frac{dr}{dt} = 3\,\frac{cm}{min}

Our unknown is the rate at which the area (A) of the circle is growing under these circumstances,that is, we need to find  \frac{dA}{dt}.

So we look into a formula for the area (A) of a circle in terms of its radius (r), so as to have a way of connecting both quantities (A and r):

A=\pi\,r^2

We now apply the derivative operator with respect to time (\frac{d}{dt}) to this equation, and use chain rule as we find the quadratic form of the radius:

\frac{d}{dt} [A=\pi\,r^2]\\\frac{dA}{dt} =\pi\,*2*r*\frac{dr}{dt}

Now we replace the known values of the rate at which the radius is growing ( \frac{dr}{dt} = 3\,\frac{cm}{min}), and also the value of the radius (r = 12 cm) at which we need to find he specific rate of change for the area :

\frac{dA}{dt} =\pi\,*2*r*\frac{dr}{dt}\\\frac{dA}{dt} =\pi\,*2*(12\,cm)*(3\,\frac{cm}{min}) \\\frac{dA}{dt} =226.19467 \,\frac{cm^2}{min}\\

which we can round to one decimal place as:

\frac{dA}{dt} =226.2 \,\frac{cm^2}{min}

4 0
4 years ago
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