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3 years ago

How do I solve 3(x+1)=5(x−2)+7?

Mathematics

2 answers:

Zepler [3.9K]3 years ago

3 0

Answer:

Step-by-step explanation:

$3\left(x+1\right)=5\left(x-2\right)+7\\Expand\\3x+3 =5x -10+7\\Collect \:like\: terms\\3x-5x = -10+7-3\\-2x = -6\\Divide \:both\:sides\:of\:the\:equation\:by\:-2\\\frac{-2x}{-2} = \frac{-6}{-2}\\ \\x = 3$

timofeeve [1]3 years ago

3 0

Answer:

x = 3

Step-by-step explanation:

3(x+1)=5(x−2)+7

Use the distributive property to multiply 3 by x+1.

3x+3=5(x−2)+7

Use the distributive property to multiply 5 by x−2.

3x+3=5x−10+7

Add −10 and 7 to get −3.

3x+3=5x−3

Subtract 5x from both sides.

3x+3−5x=−3

Combine 3x and −5x to get −2x

−2x+3=−3

Subtract 3 from both sides.

−2x=−3−3

Subtract 3 from −3 to get −6.

−2x=−6

Divide both sides by −2.

x = -6/2

Divide −6 by −2

x = 3

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