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kumpel [21]
3 years ago
9

Randy is building a cube-shaped doghouse with four faces. He is leaving one face open as a door, and one face open to the ground

. The doghouse will be 4 feet long. What is the total surface area of the walls and the top of the doghouse?
Be sure to include the formula for surface area.

Show how to modify the forumla for surface area to meet the needs of this problem.

Show all of your work, including your final answer with the correct units
Mathematics
1 answer:
astraxan [27]3 years ago
7 0
Total suface area of a cube = 6 a^{2}, where a is the length of the cube.
Here, two faces will be left open, which reduces the formula to
total surface area = 4 a^{2}=4(4)^{2}=4\times 16=64 square feet


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A grocery store sells a bag of 5 lemons for 2$. watnis the unit cost of each lemon in the bag
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Answer:

$0.4

Step-by-step explanation:

Unit cost = cost / number of items

Unit cost = 2/5

2 divided by 5

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Explain how you would use the number line to solve the following equation. You can write out the fraction names or use the forwa
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4 0
2 years ago
What is the following product
Genrish500 [490]

For this case we must find the product of the following expression:

\sqrt [3] {5} * \sqrt {2}

By definition of properties of powers and roots we have:

\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}

We rewrite the expression using the lowest common index of 6, then:

5 ^ {\frac {1} {3}} * 2 ^ {\frac {1} {2}} =

We rewrite the terms in an equivalent way:

5 ^ {\frac {2} {6}} * 2 ^ {\frac {3} {6}} =

We rewrite the expression using the property mentioned:

\sqrt [6] {5 ^ 2} * \sqrt [6] {2 ^ 3} =

We combine using the product rule for radicals:

\sqrt [n] {a} * \sqrt [n] {b} = \sqrt [n] {ab}

So:

\sqrt [6] {5 ^ 2 * 2 ^ 3} =\\\sqrt [6] {25 * 8} =\\\sqrt[6]{200}

ANswer:

Option b

4 0
3 years ago
Use the diagram to determine which statement is true
hichkok12 [17]
A. Area of ABCD - Area of DGA = Area of DEFG
s^2 - 1/2bh = s^2
(5)^2 - 1/2(4)(3) = (3)^2
25 - 1/2(12) = 9
25 - 24 = 9
1 not equal to 9

B. Area of ABCD - Area of GHIA = Area of DGA
s^2 - s^2 = 1/2bh
(5)^2 - (4)^2 = 1/2(4)(3)
25 - 16 = 1/2(12)
9 not equal to 6

C. Area of ABCD + Area of DGA = Area of GHIA
s^2 + 1/2bh = s^2
(5)^2 + 1/2(4)(3) = (4)^2
25 + 1/2(12) = 16
25 + 6 = 16
31 not equal to 16

D. Area of DEFG + Area of GHIA = Area of ABCD
s^2 + s^2 = s^2
(3)^2 + (4)^2 = (5)^2
9 + 16 = 25
25 = 25

The answer is D.
5 0
3 years ago
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NARA [144]

Answer:

x ≤ 1/3

Step-by-step explanation:

6 0
3 years ago
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