Well, if you're rounding to 1 significant figure, which you'll mostly be asked to do,
You look and see which number is the first one which isn't a zero. The most significant. In this example, the 8. You then need to look at the second number, it's a zero. It has no value and doesn't do anything to the 8. The number after that gets rounded down to a zero, it's too far away to effect the 8, and even if it could it's too low.
The answer is 8.
(Sorry if my answer was a bit complicated...)
Answer:
3=1×5-2
Step-by-step explanation:
you minus 5-2 is 3 and one threes three
Answer:
8x + 40y
Step-by-step explanation:
<u>Step 1: Distribute</u>
4(2x + 10y)
(4 * 2x) + (4 * 10y)
(8x) + (40y)
<em>8x + 40y</em>
<em />
Answer: 8x + 40y
If you are solving for x, you could set it up like this:
x + 8 = 2x + 5
-5 - 5
x + 3 = 2x
-x -x
3 = x
So now that you have the value of x. You can plug it in. The first one is x + 8 or 3 + 8 since the value of x is 3. Then the next one is 2x + 5 or 2(3) + 5.