I don't know about the circle, but from the way it looks, you can use pythagorean theorem (A^2+B^2=C^2). angle E would be the Right Angle making 65=C or in other words, the hypotenuse, with 60 and Line ED being the legs (it doesn't matter which is A and which is B) leaving the equation
60^2+B^2=65^2 and solve from there. (if you need help solving, leave a comment and i will walk you through it in the comments)
Equation of line passing through given points :
Let's proceed with two point form ~
Assume :
So, the equation of required line is : y = 3 ~
Answer: D
Step-by-step explanation:
Answer:
m∠CBD=68°
Step-by-step explanation:
BA is perpendicular to BD, meaning they form a right angle (90°)
This means m∠CBD + m∠ABC=90, or they are supplementary.
We have expressions given for these angles, so
4x+52+8x-10=90
12x+42=90
12x=48
x=4
Knowing x=4, we can substitute back into our expression for m∠CBD because that's what we're looking for.
4(4)+52=68
m∠CBD is 68°.
usa pothomath (no me acuerdo como se escribe)
