What is the surface area? 9 ft 6 ft 3 ft square feet

Cody was looking at his streaming music stats. The Ratio of songs he liked to disliked was 5:6. If he listened to 1,078 songs to

aivan3 [116]

1078 / (5+6) = 98
Like - 5 x 98 = 490
Dislike - 6 x 98 = 588

6 0

3 years ago

Help please! Thank you!!

umka2103 [35]

Answer:

i dont know what it is

Step-by-step explanation:

maybe a

3 0

3 years ago

It was estimated that because of people switching to Metro trains about 33000 of CNG 3300 tons of diesel and 21000 tons of petro

Simora [160]

The question is incomplete. Here is the complete question

It was estimated that because of people switching to Metro trains about 33000 of CNG 3300 tons of diesel and 21000 tons of petrol was saved by the end of year 2007 (I) find a fraction of the quantity of diesel saved to the quantity of petrol saved (ii) find the quantity of cng to the quantity of diesel saved

Answer:

(I) 11/70

(II) 1/10

Step-by-step explanation:

Metro trains contain 330,000 tons of CNG

3300 tons of diesel was saved

21000 tons of petrol was saved at the end of 2007

(I) The fraction of the quantity of diesel saved to the quantity of petrol saved can be calculated as follows

= 3300/21000

= 11/70

(II) The fraction of the quantity of CNG saved to the quantity of diesel can be calculated as follows

= 3300/33000

= 1/10

5 0

3 years ago

The National Center for Education Statistics surveyed a random sample of 4400 college graduates about the lengths of time requir

Paha777 [63]

Answer:

95% confidence interval for the mean time required to earn a bachelor’s degree by all college students is [5.10 years , 5.20 years].

Step-by-step explanation:

We are given that the National Center for Education Statistics surveyed a random sample of 4400 college graduates about the lengths of time required to earn their bachelor’s degrees. The mean was 5.15 years and the standard deviation was 1.68 years respectively.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean time = 5.15 years

$\sigma$ = sample standard deviation = 1.68 years

n = sample of college graduates = 4400

$\mu$ = population mean time

Here for constructing 95% confidence interval we have used One-sample z test statistics although we are given sample standard deviation because the sample size is very large so at large sample values t distribution also follows normal.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5%

level of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95