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3 years ago

2. What's the area of the figure, which has sides of length 6 and 8? A. 42 B. 48 C. 28 D. 14

Mathematics

2 answers:

Natasha2012 [34]3 years ago

8 0

Answer:

B. 48

Step-by-step explanation:

The area of a rectangle is length times width

A = l*w

A = 6*8

A = 48

Aneli [31]3 years ago

5 0

Answer:

B. 48

Step-by-step explanation:

for area you multiply the 2 numbers given in this case

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3 years ago

Which are sums of perfect cubes? Check all that apply. 8x6 27 x9 1 81x3 16x6 x6 x3 27x9 x12 9x3 27x9.

Black_prince [1.1K]

The equations which are sums of perfect cubes are as follows;

$\rm 8x^6+27x^9+1$

$\rm x^6+x^3$

$\rm 27x^9+x^{12}$

<h3>Perfect cubes;</h3>

Perfect cubes are the numbers that are the triple product of the same number.

We have to determine

Which are sums of perfect cubes?

1. The given equation is $\rm 8x^6+27x^9+1$ .

The equation can be written as;

$\rm 8x^6+27x^9+1\\\\2^3(x^2)^3+3^3(x^3)^3+1^3$

All the terms in the expression are can be represented as perfect cubes.

2. The given equation is $\rm 81x^3+16x^6$ .

The equation can be written as;

$\rm 81x^3+16x^6\\\\9^2x^3+4^2(x^2)3$

In this, all the terms are not perfect cubes, some of them are squares.

3. The given equation is $\rm x^6+x^3$ .

The equation can be written as;

$\rm x^6+x^3\\\\(x^2)^3+x^3$

All the terms in the expression are perfect cubes.

4. The given equation is $\rm 27x^9+x^{12}$ .

The equation can be written as;

$\rm 27x^9+x^{12}\\\\3^3(x^3)^3+(x^4)^3$

All the terms in the expression are perfect cubes.

5. The given equation is $\rm 9x^3+27x^9$ .

The equation can be written as;

$\rm 9x^3+27x^9\\\\3^2x^3+3^3(x^3)^3$

In this, all the terms are not perfect cubes, some of them are squares too.

To know more about perfect cubes click the link given below.

brainly.com/question/4701925

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