substitute for your equation;
h(x) = f(x) - g(x)
h(x) = (3x + 2) - (-2x -4)
h(x) = 3x + 2 + 2x + 4 (minus and minus = addition)
h(x) = 3x + 2x + 2 + 4 (combine like terms)
h(x) = 5x + 6
Hope that helps! :D
Answer:
Simplified: -4a²b²+18a³-2b³
3a(6a²-4ab²)+8a²b²-2b³
Multiply 3a by 6a² and-4ab²
18a³-12a²b²+8a²b²-2b³
combine like terms (-12a²b² and 8a²b²)
-4a²b²+18a³-2b³
Hope this helps
The <em><u>correct answer</u></em> is:
An integer is divisible by 100 if its last two digits are zeros; and An integer's last two digits are zero if it is divisible by 100.
Explanation:
A biconditional is a statement made up of a true conditional and its converse. The converse of a conditional statement is formed by switching the hypothesis and the conclusion of the conditional.
The first statement in the biconditional is An integer is divisible by 100 if its last two digits are zeros. The converse of this would be An integer's last two digits are zeros if it is divisible by 100. Joining these using "if and only if" creates our biconditional.
