Just apply the Pythagoras Theorem,
LN² = LM² + MN²
LN² = 7² + 8²
LN² = 49 + 64
LN = √113
In short, Your Answer would be: Option D
Hope this helps!
Given:
The largest circle has a radius of R=7 units.
Let x be the radius of the large shaded circle.
The small shaded circles have a radius of 1/5 of the large shaded circle.
=> the small shaded circles have a radius of r=x/5
By adding up radii, we have the equation
2(r+x+r)=2(x/5+x+x/5)=2R=2*7=14
Simplify:
7x/5=14/2
x=5
=> r=1
Area of outer circle =

Area of large shaded circle =

Area of 4 small shaded circles =

Total area of shaded circles =

Shaded area as a fraction of that of the outer circle
The equation that has an infinite number of solutions is 
<h3>How to determine the equation?</h3>
An equation that has an infinite number of solutions would be in the form
a = a
This means that both sides of the equation would be the same
Start by simplifying the options
3(x – 1) = x + 2(x + 1) + 1
3x - 3 = x + 3x + 2 + 1
3x - 3 = 4x + 3
Evaluate
x = 6 ----- one solution
x – 4(x + 1) = –3(x + 1) + 1
x - 4x - 4 = -3x - 3 + 1
-3x - 4 = -3x - 2
-4 = -2 ---- no solution

2x + 3 = 2x + 1 + 2
2x + 3 = 2x + 3
Subtract 2x
3 = 3 ---- infinite solution
Hence, the equation that has an infinite number of solutions is 
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<u>Complete question</u>
Which equation has infinite solutions?
3(x – 1) = x + 2(x + 1) + 1
x – 4(x + 1) = –3(x + 1) + 1


The solution of the equation is x = 2
Step-by-step explanation:
The original equation is

We solve it using the following steps:
1) We apply the addition property of equality: by adding the same factor on both sides of the equation, the equation does not change.
In this case, we add +10 on both sides, and we get:

2) We apply the division property of equality: by dividing both sides of the equation by the same number (different from zero), the equation does not change.
In this case, we divide both sides of the equation by 5, and we get:

Therefore, the solution of the equation is
.
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