2(11+13) = 26+2w because 2(11)=22 2(13)=26
(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.
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(b) The following functions are positive in quadrant III:
tangent, cotangent
The following functions are negative in quadrant III
cosine, sine, secant, cosecant
A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.
<span>The relation described in this statement can be classified as </span><span>both a relation and a function. </span>
Answer:
(a)There are 24 cakes in total
(b)There are 15 pieces of cakes left
Step-by-step explanation:
Let the total cakes=x
Let number of cakes eaten by Mindy=m
Let number of cakes eaten by Troy=t
Now:
m=3
Since m+t=9
3+t=9
t=9-3=6
The Number of Pieces of Cake Left in Total=x-(t+m)
Since Troy had 
of the total cake
x=6X4=24
(a)There are 24 cakes in total
(b)The Number of Pieces of Cake Left in Total=x-(t+m)=24-9=15 cakes
Earth: radius = 6378 kilometer, diameter = 12756 kilometers.
