Answer:
1.544*10⁹ Linebackers would be required in order to obtain the same density as an alpha particle
Step-by-step explanation:
Assuming that the pea is spherical ( with radius R= 0.5 cm= 0.005 m), then its volume is
V= 4/3π*R³ = 4/3π*R³ = 4/3*π*(0.005 m)³ = 5.236*10⁻⁷ m³
the mass in that volume would be m= N*L (L= mass of linebackers=250Lbs= 113.398 Kg)
The density of an alpha particle is ρa= 3.345*10¹⁷ kg/m³ and the density in the pea ρ will be
ρ= m/V
since both should be equal ρ=ρa , then
ρa= m/V =N*L/V → N =ρa*V/L
replacing values
N =ρa*V/L = 3.345*10¹⁷ kg/m³ * 5.236*10⁻⁷ m³ /113.398 Kg = 1.544*10⁹ Linebackers
N=1.544*10⁹ Linebackers
Answer: 9 over 12 is = 15 over x
Step-by-step explanation:
Answer:
5.83
Step-by-step explanation:
Answer:
$3 max
Step-by-step explanation:
Charge= b, Customer= c, Revenue= r
r= bc, currently, r= 16*10= $160
We know that: b+1 ⇒ c-2 and the target is r ≥ 130
So, this will all be reflected as:
b=10+x ⇒ c= 16-2x
- (10+x)(16-2x) ≥ 130
- 160 -20x +16x - 2x² ≥ 130
- -2x² - 4x + 30 ≥ 0
- x² + 2x -15 ≤ 0
- (x+1)² ≤ 4²
- x+1 ≤ 4 (negative value not considered)
- x ≤ 3
As we see the max increase amount is $3, when the revenue will be:
(10+3)*(16-3*2)= 13*10= $130
Answer:
it's a quadratic formula
Step-by-step explanation:
in the formula, substitute the value of <u>a as 1, b as 2 and c as -8</u>
then, you will get ur answer
