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kondaur [170]
3 years ago
13

A $1,500 savings bond earns simple interest at the rate of 5% each year. The interest is paid at the end of every month. How muc

h interest will the bond have earned after 4 months?
For Math test due in 14 minutes!!
Mathematics
2 answers:
ivanzaharov [21]3 years ago
7 0
The answer is 300 have a good day
kirill [66]3 years ago
4 0

Answer:

300

Step-by-step explanation:

5 percent * 6000

(5:100)* 6000

(5* 6000):100

30000:100 = 300

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(x. y)=  (4,-6)

Step-by-step explanation:

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<h3>Answer: Choice A</h3>

x^2\left(\sqrt[4]{x^2}\right)

=====================================================

Explanation:

The fourth root of x is the same as x^(1/4)

I.e,

\sqrt[4]{x} = x^{1/4}

The same applies to x^10 as well

\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4}

Multiply the exponents 10 and 1/4 to get 10/4

\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4} = x^{10*1/4} = x^{10/4}

\sqrt[4]{x^{10}} = x^{10/4}

-----------------------

If we have an expression in the form x^(m/n), with m > n, then we can simplify it into an equivalent form as shown below

x^{m/n} = x^a\sqrt[n]{x^b}

The 'a' and 'b' are found through dividing m/n

m/n = a remainder b

'a' is the quotient, b is the remainder

-----------------------

The general formula can easily be confusing, so let's replace m and n with the proper numbers. In this case, m = 10 and n = 4

m/n = 10/4 = 2 remainder 2

We have a = 2 and b = 2

So

x^{m/n} = x^a\sqrt[n]{x^b}

turns into

x^{10/4} = x^2\sqrt[4]{x^2}

which means

\sqrt[4]{x^{10}} = {x^2} \sqrt[4]{x^2}

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Answer:

I believe it's 192

Step-by-step explanation:

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