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mel-nik [20]
3 years ago
15

If 14y - 4 = 24y + 26 , then 12y =

Mathematics
2 answers:
timofeeve [1]3 years ago
5 0
14y - 4 = 24y + 26
-4 - 26 = 24y - 14y
-30 = 10y
10y = -30
y =- -30/10
y = -3
12y =12(-3)
12y = -36
harkovskaia [24]3 years ago
4 0
Solutions 

To solve the equation we have to isolate 12y

14y - 4 = 24y + 26

-4 - 26 = 24y - 14y

-30 = 10y

10y = -30

y =- -30/10

y = -3

12y =12/-3

12y = -36

Therefore, 12y = -36
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80 minutes or 1 h 20 minutes

Step-by-step explanation:

15-13=2

2/0.025=80

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Alja [10]

1. The answer is 16^2, so B.

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2. The answer is 17, so B.

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Only 15 is composite since it contains more than a factor, which are 3 and 5. The rest of the numbers are prime since they only contain a factor.

4. The answer is 2^2^3^7, so B.

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3 0
3 years ago
What is the strongest classification of the figure formed by the following points?
tatiyna

Answer:

A. Parallelogram

Step-by-step explanation:

The given points are;

(-10, -4), (-7, -8), (-5, -4), (-2, -8)

Let 'A' represent the point (-10, -4), let 'B' represent the point (-7, -8), let 'C' represent the point (-5, -4), and let 'D' represent the point (-2, -8), we have;

The (horizontal) distance between points A and C = -5 - (-10) = 5

The (horizontal) distance between points B and D = -2 - (-7) = 5

Therefore;

The length of \overline {AC} = The length of \overline {BD}

The length of \overline {AB} = √((-10 - (-7))² + (-4 - (-8))²)) = 5

The length of \overline {CD} = √((-5 - (-2))² + (-4 - (-8))²)) = 5

∴ The length of \overline {AB} = The length of \overline {CD}

\overline {AC} is parallel to the horizontal axis

\overline {BD} is parallel to the horizontal axis

∴ \overline {AC} ║ \overline {BD}

Given that \overline {AB} = \overline {CD}, then \overline {AB} ║ \overline {CD}

Therefore, the quadrilateral ABCD is a parallelogram

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6 0
2 years ago
Please help, thank you
madam [21]

Answer:

\displaystyle x=\frac{-8\pm\sqrt{(8)^2-4(4)(-221)}}{2(4)}\ \text{; x = 6.5 and x = -8.5}

Step-by-step explanation:

Subtract the right side of the given equation to put it into standard form:

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Then the coefficients used in the quadratic formula are ...

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When these are filled into the form ...

\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

the result is as shown above.

7 0
3 years ago
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