Answer:
![\bar X =\frac{2.3+3.1+2.8+1.7+0.9+4+2.1+1.2+3.6+0.2+2.4+3.2}{12}=2.29](https://tex.z-dn.net/?f=%5Cbar%20X%20%3D%5Cfrac%7B2.3%2B3.1%2B2.8%2B1.7%2B0.9%2B4%2B2.1%2B1.2%2B3.6%2B0.2%2B2.4%2B3.2%7D%7B12%7D%3D2.29)
![s=1.09](https://tex.z-dn.net/?f=%20s%3D1.09)
Step-by-step explanation:
For this case we have the following data given:
2.3 3.1 2.8
1.7 0.9 4.0
2.1 1.2 3.6
0.2 2.4 3.2
Since the data are assumedn normally distributed we can find the standard deviation with the following formula:
![\sigma =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}](https://tex.z-dn.net/?f=%5Csigma%20%3D%5Csqrt%7B%5Cfrac%7B%5Csum_%7Bi%3D1%7D%5En%20%28X_i%20-%5Cbar%20X%29%5E2%7D%7Bn%7D%7D)
And we need to find the mean first with the following formula:
![\bar X = \frac{\sum_{i=1}^n X_i}{n}](https://tex.z-dn.net/?f=%5Cbar%20X%20%3D%20%5Cfrac%7B%5Csum_%7Bi%3D1%7D%5En%20X_i%7D%7Bn%7D)
And replacing we got:
![\bar X =\frac{2.3+3.1+2.8+1.7+0.9+4+2.1+1.2+3.6+0.2+2.4+3.2}{12}=2.29](https://tex.z-dn.net/?f=%5Cbar%20X%20%3D%5Cfrac%7B2.3%2B3.1%2B2.8%2B1.7%2B0.9%2B4%2B2.1%2B1.2%2B3.6%2B0.2%2B2.4%2B3.2%7D%7B12%7D%3D2.29)
And then we can calculate the deviation and we got:
![s=1.09](https://tex.z-dn.net/?f=%20s%3D1.09)
Answer:
%35 of them were in color
Step-by-step explanation:
Since 30 percent of the first 200 sold were in color, 200x30/100 = 60 of them were in color.
Since 20 percent of the next 300 sold were in color, 300x20/100 = 60 of them were in color.
Since 90 percent of the last 100 sold were in color, 100x90/100 = 90 of them were in color.
In total, 60 + 60 + 90 = 210 out of 600 were in color.
The percentage is:
=
→ x =
= 35
Brown oooOiejdjdjdjdieoeidididieoddo gg 1919912
Answer:4 terms
Step-by-step explanation:
Terms can be every one of them. Even if they have or don't have a variable.